16.Use Linear programming for following study by drawing graph.Problem definition: Beaver Creek Maximization problemProduct mix problem - Beaver Creek Pottery Company: How many bowls and mugs shouldbe produced to maximize profits given labor and materials constraints?Product resource requirements and unit profit:Resource RequirementsClay(Ib/unit)LaborProfitProduct(hr/unit)($/unit)Bowl1.40Mug235040 hrs of labor per day120 Ibs of clayResourceAvailability:Decision Variables x; = number of bowls to produce per daynumber of mugs to produce per dayObjectiveMaximize Z = $40x, + $50x,Where z = profit per day1x, + 2x, 5 40 hours of laborFunction:Resource4x, + 3x2 s 120 pounds of clayX; 2 0; X, 20Constraints:Non-NegativityConstraints:

To solve the given linear programming problem using the graphical method. Concepts used:To solve a…

Problem definition: Beaver Creek Maximization problem Product mix problem - Beaver Creek Pottery Company: How many bowls and mugs should be produced to maximize profits given labor and materials constraints? Product resource requirements and unit profit. Product Bowl Mug Resource Requirements Constraints: Non-Negativity Constraints: Labor (hr/unit) 1 2 Resource Availability: Decision Variables number of mugs to produce per day Objective Function: Resource Clay (lb/unit) 4 3 40 hrs of labor per day 120 lbs of clay x₁ = number of bowls to produce per day Maximize Z = $40x, + $50x₂ Where Z-profit per day 1x, + 2x, ≤ 40 hours of labor Profit ($/unit) 40 50 4x₁ + 3x₂ ≤ 120 pounds of clay x₁ ≥ 0; x ≥ 0 X₂=

Problem definition: Beaver Creek Maximization problem Product mix problem - Beaver Creek Pottery Company: How many bowls and mugs should be produced to maximize profits given labor and materials constraints? Product resource requirements and unit profit. Product Bowl Mug Resource Requirements Constraints: Non-Negativity Constraints: Labor (hr/unit) 1 2 Resource Availability: Decision Variables number of mugs to produce per day Objective Function: Resource Clay (lb/unit) 4 3 40 hrs of labor per day 120 lbs of clay x₁ = number of bowls to produce per day Maximize Z = $40x, + $50x₂ Where Z-profit per day 1x, + 2x, ≤ 40 hours of labor Profit ($/unit) 40 50 4x₁ + 3x₂ ≤ 120 pounds of clay x₁ ≥ 0; x ≥ 0 X₂=

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section: Chapter Questions

Problem 13T

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