Determine the nominal axial compressive strength of the members shown in the following figure. 1. Pipe 10 std. ASTM A53 Grade B (F,= 35 ksi)
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- Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.The following image shows a front and side view of the column connection. The bolts have a diameter of ¾”. The W12X65 profile has a thickness of 0.605”. Determine: a. The shear stress in the bolts. Answ. 11.81 ksi b. The axial stress in the bolts. Answ. 23.62 ksi c. The support stress in the W12X65 profile. 11.50 ksiCompute the size of fillet weld for a bracket connection with ISMB 300 column as shown in figure. Permissible shear stress in weld = 110 MPa. %3D 425 mm 100 kN 300 Single 12 mm plate 250 mm
- A bolted connection shown consists of two plates 300mm x12mm connected by 4 - 22 mm diameter bolts. Edge distances = 75mm dhole for tensile and rupture = db + 3 mm dhole for bearing strength for Lc = db + 1.5 mm Fy = 248 Mpa Fu = 400 Mpa Fn = 330 Mpa Use LRFD design method. Determine the design strength due to the gross yielding of plates. (kN)a welded connection is in eqilibrium under the action of the four forces shown. Knowing that FA=8lbs and FB= 16lbs, determine the magnitudes of other two forces *3dec places all final2. See connection figure below. The rivets is 7/8 in. in diameter. According to the rivert supplier, the allowable stresses for the material are t = 15 ksi and on = 32 ksi. What is the allowable load of the connection? L4 x 3-1/2 W18 x 86 W24 x 117 Girder Beam
- Six rivets are used in the connection shown in the figure. If both P=50KN, what is the minimum diameter rivet is necessary so as not exceed the 70MPa allow shearing stress? What thickness of plate is required so as not exceed a bearing stress of 140MPA? p= 50 80 mm 80 mm 100 mmA PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H FO E. • D A ВThe five-bolt connection shown must support an applied load of P = 300 N. The thickness of the axial member: = 1.5 mm. and the width = 18 mm If the ultimate shear stress in the bolts must be limited to 265 MPa with F.O.S = 3.7 . And the ultimate normal stress in the axial member = 250 MPa, with F.O.S = 2.8 , And the ultimate bearing stress in the axial member = 110 MPa, F.O.S = 2.5 Determine the minimum bolt diameter that may be used in the connection
- 2 ISA 75 x 75 x 8 carry a load of 150 kN and are placed back to back through a 6 mm gusset plate. The permissible shear stress is 100 MPa and bearing stress is 300 MPa. Design the riveted connection and show the arrangement with a neat sketch.A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H G P P D B F C A EThe following image shows a front and side view of the column connection. The bolts have a diameter of ¾”. The W12X65 profile has a thickness of 0.605”. Determine:a. The shear stress in the bolts.b. The axial stress in the bolts.c. The support stress in the W12X65 profile.