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Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 300 N.m. M, A C X2 X1 -

Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 300 N.m. M, A C X2 X1 -

Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.14P: Solve the preceding problem for the following data: x=1120106,y=430106,xy=780106,and=45.
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Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 300 N.m. M, A X1 - X2 5 т 2 m Select one: V1 (x) =(1/EI). (10 x - 250 x1) {m) and V2 (x) = (1/EI). (150 x2 - 1100 xz+ 1600) {m} %3D
Transcribed Image Text:Determine the equations of the elastic curve for the shaft using the x1 and x2 coordinates. Take El as constant and Mo = 300 N.m. M, A X1 - X2 5 т 2 m Select one: V1 (x) =(1/EI). (10 x - 250 x1) {m) and V2 (x) = (1/EI). (150 x2 - 1100 xz+ 1600) {m} %3D
Select one: V1 (x) =(1/EI). (10 x1² – 250 x1) {m} and V2 (x) = (1/EI). (150 x, - 1100 x,+ 1600) {m} v1 (x) =(1/E). (10 x1 - 250 x1) {m} and V2 (x) = (1/EI). (-150 x;² + 1100 x2 - 1600) {m} V1 (X) =(1/E). (10 x, + 250 x1) (m) and V2 (X) = (1/EI). (150 x, + 1100 xX2 - 1600) (m) %3D V1 () -(1/EI). (10 x1 + 250 x1) {m} and V2 (x) = (1/ED. (150 x2 – 1100 x2+ 1600) (m) V1 (x) =(1/EI) (-10 x - 250 x,) (m) and V2 (x) = (1/EI). (-150 x,² – 1100 x,+ 1600) {m)
Transcribed Image Text:Select one: V1 (x) =(1/EI). (10 x1² – 250 x1) {m} and V2 (x) = (1/EI). (150 x, - 1100 x,+ 1600) {m} v1 (x) =(1/E). (10 x1 - 250 x1) {m} and V2 (x) = (1/EI). (-150 x;² + 1100 x2 - 1600) {m} V1 (X) =(1/E). (10 x, + 250 x1) (m) and V2 (X) = (1/EI). (150 x, + 1100 xX2 - 1600) (m) %3D V1 () -(1/EI). (10 x1 + 250 x1) {m} and V2 (x) = (1/ED. (150 x2 – 1100 x2+ 1600) (m) V1 (x) =(1/EI) (-10 x - 250 x,) (m) and V2 (x) = (1/EI). (-150 x,² – 1100 x,+ 1600) {m)
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