Consider the reversible formation of the Cu(NH3)4 complex ion. 2+ Cu?+ (aq) + 4NH3 (aq) – Cu(NH3)4** (aq) Suppose you have a solution at equilibrium in which [Cu1= 0.415 M, NH3] = 0.304 M, and [Cu(NH3)42"] = 0.148 M . What is the value of the formation constant for the system at these conditions?

Chemistry: An Atoms First Approach
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Chapter15: Solubility And Complex Lon Equilibria
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Consider the reversible formation of the Cu(NH3)4 complex ion.
2+
Cu²+ (aq) + 4NH3 (aq) Cu(NH3)4²+ (aq)
Suppose you have a solution at equilibrium in which [Cu= 0.415 M.
%3D
NH3] = 0.304 M, and (Cu(NH3)42+] = 0.148 M .
What is the value of the formation constant for the system at these conditions?
Type answer:
Transcribed Image Text:Consider the reversible formation of the Cu(NH3)4 complex ion. 2+ Cu²+ (aq) + 4NH3 (aq) Cu(NH3)4²+ (aq) Suppose you have a solution at equilibrium in which [Cu= 0.415 M. %3D NH3] = 0.304 M, and (Cu(NH3)42+] = 0.148 M . What is the value of the formation constant for the system at these conditions? Type answer:
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