|The solubility of cadmium oxalate, CdC2 04, in 0.150 M ammonia is 6.1 × 10-8 mol/L. What is the oxalate ion concentration in the saturated solution? If the solubility product constant for cadmium oxalate is 1.5 x 10-8, what must be the cadmium ion concentration in the solution? Now, calculate the formation constant for the complex ion Cd(NH3)42+. [C20,2] = | м (Ca²*] =| |м K; =

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Chapter17: Solubility And Complex-ion Equilibria
Section: Chapter Questions
Problem 17.94QP: The solubility of cadmium oxalate. CdC2O4, in 0.150 M ammonia is 6.1 103 mol/L. What is the...
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|The solubility of cadmium oxalate, CdC2 04, in 0.150 M ammonia is 6.1 × 10-8 mol/L. What is the oxalate ion
concentration in the saturated solution? If the solubility product constant for cadmium oxalate is 1.5 x 10-8, what must be
the cadmium ion concentration in the solution? Now, calculate the formation constant for the complex ion Cd(NH3)42+.
[C20,2] = |
м
(Ca²*] =|
|м
K; =
Transcribed Image Text:|The solubility of cadmium oxalate, CdC2 04, in 0.150 M ammonia is 6.1 × 10-8 mol/L. What is the oxalate ion concentration in the saturated solution? If the solubility product constant for cadmium oxalate is 1.5 x 10-8, what must be the cadmium ion concentration in the solution? Now, calculate the formation constant for the complex ion Cd(NH3)42+. [C20,2] = | м (Ca²*] =| |м K; =
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