Consider the following equilibrium reactions, which is the first step in the commercial process of nitric acid: Delta H: -905.6 kJ 4 NH3 (g) + 5 NO2 (aq) = 4 NO (g) + 6 H2O (g) QUESTION: How would increasing the concentration of water effect the equilibrium?  Shifting it left or right?

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
Section4.7: Where Does The Energy Come From?
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Consider the following equilibrium reactions, which is the first step in the commercial process of nitric acid:

Delta H: -905.6 kJ

4 NH3 (g) + 5 NO2 (aq) = 4 NO (g) + 6 H2O (g)

QUESTION: How would increasing the concentration of water effect the equilibrium? 

Shifting it left or right? - Please explain so I can understand why! 
Thank you!

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