Calculate the K, from the following data. start: equil: Ka Ka H₂S 1.000 M 0.9923 M 0.0077 M + g. HF(aq) n. HPO ² u. H₂O(lig) aa. 0.9923 2 H₂O The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us Thus, M H₂S will give ][ S X 2 H₂O+ 0 0.0154 M c. phosphoric the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic b. hydrochloric d. Al+3 h. CaCO3(s) i. OH-¹ k. SO4² o. H₂PO4-¹ P. CO32 r. H₂S v. H₂CO3 W. PO4³ bb. 0.0077 cc. 3 j. H30+1 q. HCO3-¹ + x. HC2H3O2 dd. 2 S-² 0 0.0077 M 1² e. CO₂ MS-2 and M mol of S-² and 1. Mg+2 s. HS-1 y. C₂H30₂-1 ee. 1 ff. 0.0154 f. CaF2(aq) m. CI-1 t. 5-² Z. 1 x 10-14 gg. 3.95 x 10-3 mol of H30+1 M H30+1

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 36QAP: At a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s),...
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Calculate the K₂ from the following data.
H₂S
1.000 M
0.9923 M
0.0077 M
start:
equil:
K₂ =
Ka
+
2 H₂O
The amount of H₂S that was converted into product is
The stoichiometry tells us that 1 mol H₂S will give us
Thus,
M H₂S will give
u. H₂O(lig)
aa. 0.9923
hh. 1.84 x 10-6
5
][
2 H₂O+
0
0.0154 M
b. hydrochloric c. phosphoric
h. CaCO3(s) i. OH-1
j. H30+1
0. H₂PO4-¹ p. CO3²
q. HCO3-¹
v. H₂CO3 W. PO4³
cc. 3
bb. 0.0077
ii. 0.01250
+
the concentration of [H3O+¹] is squared because its coefficient is 2
a. acetic
d. Al+3
k. SO4²
g. HF (aq)
n. HPO ²
r. H₂S
S-²
0
0.0077 M
x. HCzH3O2
dd. 2
1²
jj. 0.22100 kk. 0.05656
MS-² and
e. CO₂
M
mol of S-² and
y. C₂H30₂-1
ee. 1 ff. 0.0154
1. Mg+2
S. HS-1
f. CaF2(aq)
m. CI-1
t. S-2
z. 1 x 10-14
gg. 3.95 x 10-3
mol of H30+1
M H30+1
Transcribed Image Text:Calculate the K₂ from the following data. H₂S 1.000 M 0.9923 M 0.0077 M start: equil: K₂ = Ka + 2 H₂O The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us Thus, M H₂S will give u. H₂O(lig) aa. 0.9923 hh. 1.84 x 10-6 5 ][ 2 H₂O+ 0 0.0154 M b. hydrochloric c. phosphoric h. CaCO3(s) i. OH-1 j. H30+1 0. H₂PO4-¹ p. CO3² q. HCO3-¹ v. H₂CO3 W. PO4³ cc. 3 bb. 0.0077 ii. 0.01250 + the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic d. Al+3 k. SO4² g. HF (aq) n. HPO ² r. H₂S S-² 0 0.0077 M x. HCzH3O2 dd. 2 1² jj. 0.22100 kk. 0.05656 MS-² and e. CO₂ M mol of S-² and y. C₂H30₂-1 ee. 1 ff. 0.0154 1. Mg+2 S. HS-1 f. CaF2(aq) m. CI-1 t. S-2 z. 1 x 10-14 gg. 3.95 x 10-3 mol of H30+1 M H30+1
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