Ⓒ Macmillan Learning At a certain temperature, 0.4211 mol of N₂ and 1.601 mol of H₂ are placed in a 5.00 L container. N₂(g) + 3H₂(g) → 2NH₂(g) At equilibrium, 0.1801 mol of N₂ is present. Calculate the equilibrium constant, K. Kc = || x10 TOOLS Assignment Score: Question 5 of 13 > 84.6% General Chemistry 4th Edition McQuarrie • Rock • Gallogly Kc = Resources The equilibrium constant for the chemical equation N₂(g) + 3 H₂(g) = 2NH₂(g) is Kp = 0.0328 at 201 °C. Calculate the value of K, for the reaction at 201 °C. Give Up? Hint Check Answer University Science Books presented by Macmillan Learning

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Ⓒ Macmillan Learning
At a certain temperature, 0.4211 mol of N₂ and 1.601 mol of H₂ are placed in a 5.00 L container.
N₂(g) + 3H₂(g) → 2NH₂(g)
At equilibrium, 0.1801 mol of N₂ is present. Calculate the equilibrium constant, K.
Kc =
||
x10
TOOLS
Transcribed Image Text:Ⓒ Macmillan Learning At a certain temperature, 0.4211 mol of N₂ and 1.601 mol of H₂ are placed in a 5.00 L container. N₂(g) + 3H₂(g) → 2NH₂(g) At equilibrium, 0.1801 mol of N₂ is present. Calculate the equilibrium constant, K. Kc = || x10 TOOLS
Assignment Score:
Question 5 of 13
>
84.6%
General Chemistry 4th Edition
McQuarrie • Rock • Gallogly
Kc =
Resources
The equilibrium constant for the chemical equation
N₂(g) + 3 H₂(g) = 2NH₂(g)
is Kp = 0.0328 at 201 °C. Calculate the value of K, for the reaction at 201 °C.
Give Up?
Hint
Check Answer
University Science Books
presented by Macmillan Learning
Transcribed Image Text:Assignment Score: Question 5 of 13 > 84.6% General Chemistry 4th Edition McQuarrie • Rock • Gallogly Kc = Resources The equilibrium constant for the chemical equation N₂(g) + 3 H₂(g) = 2NH₂(g) is Kp = 0.0328 at 201 °C. Calculate the value of K, for the reaction at 201 °C. Give Up? Hint Check Answer University Science Books presented by Macmillan Learning
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