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List three major peaks in the IR associated with camphor. Be certain to provide the wave numbers associated with these peaks.
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100
95
90
86
4000
11
871
18 6
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4
3000
72
3
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Wavenumber [cm-1]
2000
чтичи припини
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- ESF X empt/quiz_start_frame_auto.d21?ou=9739790&isprv=&qi=11007766&cfql=0&dnb=0&fromQB=0&inProgress=1 ystems Question 5 (1 point) Ben starts walking along a path at 3 mi hr¹. Amanda starts jogging along the same path 1 hour later at 5 mi hr. After how much time jogging does Amanda catch up to Ben? 3.5 hr 2.5 hr 2 hr 16100 - 80 40 20 20 40 60 80 100 120 140 160 180 200 220 m/z Br B Br ond onde D Br Br Relative Intensityif you know the standard deviation = 3 for measured data, what is the variance? الاختيارات 12 O зо 6 O 90
- Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any “drift†of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…Relative Intensity 100 M+ = 132 80 60 40- 20- 0- 25 50 75 m/z 100 T 1255. Express (dS/dT)p in terms of measurable properties beginning with the definition of dS and recognizing that dS=dH=CpdT.
- Q3. A cellulose coating that weighs at least 3.00 mg is often applied to the exterior of vitamin C tablets in order to delay the release of active ingredients. A random sampling of 100 vitamin tablets revealed that 6 vitamin tablets failed to meet the required weight of the cellulose coating. (а) Calculate the relative standard deviation (in %). (b) Determine the number of tablets should be taken into consideration to ensure a relative standard deviation of 15 %.PbI2 Ksp= 8.7 × 10-9Calculate the mean and 90% confidence interval for the data set. Sample Value 1 8.0626 8.0650 3 8.0583 4 8.0564 8.0571 6. 8.0600 mean: étv A A hulu 2. 5.
- Identify and provide an explanation of the differencesbetween homogeneous and heterogeneous sampling in the context of samplingmethods.In the technique of high performance liquid chromatography (HPLC) the peak area response for a particular analyte is directly proportional to concentration Analgesic tablets typically consist of aspirin and caffeine as the active ingredients, the remainder made up of inert binding material. The concentrations of aspirin and caffeine may be routinely monitored using HPLC, whereby the peak areas obtained from a solution of the tablet are compared with those obtained from standard solutions of the analytes. In an analysis to determine the concentration of caffeine in such a tablet, the following data were recorded: Solutions Analysed: Tablet Sample: Mass of tablet (dissolved in 250 cm methano): 0.523 g Caffeine Standard: Mass of caffeine (diessolved in 500 cm methanol) 0.105 g HPLC results: Solution Peak Area (catfeine) 1. Tablet Sample 325 2. Caffeine Std. 865 The concentration of caffeine in the tablet (expressed as a mass (w/wl percentage) was Oa 1.89 Ob 13.4 O 3.77 Od. 267 Oe 7.54 You…Trial I Trial II Final reading HCI 26. 40 ml 27.10 ml Initial reading HCI 1.2 ml 1.8 ml Volume of HCl used ? ? Final reading NaOH 33.7 ml 32.8 ml Initial reading NaOH 0.8 mL 0.5 ml Volume of NaOH used ? ? For trial I: Normality of NaOH : 0.25 N Vol. of HCl used = final volume - initial volume Solve for the average Normality of HCI : ? NHCI x VHCI = NNAOH x VNAOH Vol. of NaOH used = final volume - initial volume NNAOH x VNAOH For trial II: NHCI = Vol. of HCl used = final volume - initial volume VHCI Activa Vol. of NaOH used = final volume - initial volume Go to S