an AUDIO tutorial is available for this problem. Species of arsenic found in drinking water include Aso33- (arsenite), AsO43- (arsenate), (CH3)2ASO2" (dimethylarsinate), and CH3)ASO32- (methylarsonate). Pure water containing no arsenic was spiked with 0.40 µg arsenate/L. Seven replicate determinations gave 0.37, 0.38, 0.35, 0.39, 0.39, 0.35, nd 0.38 ug/L. (a) Find the mean. 4.0 pg/L Find the standard deviation. 4.0 ug/L Find the mean percent recovery of the spike. 4.0 % (b) Find the concentration detection limit. 4.0 ug/L
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- If an instrument gives a response of 1240 for a standard containing 8 ppm of a substance, how much if this substance is in a sample that gives a response of 1705? Are any assumptions needed?25 ml of pickled brine was taken from an apple pickled with vinegar and diluted to 500 ml, 25 ml of this was taken and acidity was determined with 0.2 N (Factor: 1.05) NaOH. In the main trials, 6.3 ml - 6.5 ml - 6.9 ml, respectively, 0.1 ml base was used in the analysis without using the sample.For example, how many ppm is its acidity?Sheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0
- Spike recovery and detection limit. Species of arsenic found in drinking water include AsO32 3 (arsenite), AsO32 4 (arsenate), (CH3)2AsO2 2 (dimethylarsinate), and (CH3)AsO22 3 (methylarsonate). Pure water containing no arsenic was spiked with 0.40 mg arsenate/L. Seven replicate determinations gave 0.39, 0.40, 0.38, 0.41, 0.36, 0.35, and 0.39 mg/L.15 Find the mean percent recovery of the spike and the concentration detection limit (mg/L).Spectrophotometric Determination of a Metal A 100.00 mL of exactly 250.0 mg/L Cu2+ stock solution was prepared using a 99.95% pure Cu(NO3)2-3H20 (241.60 g/mol). From this stock, a series of standard solutions were prepared by pipetting certain volumes into 100-mL volumetric flasks, followed by adding 2.00 mL of concentrated NH3, and finally diluting to mark with deionized water. Additionally, a blank solution was prepared by using only NH3 and distilled water. Question: Why was NH3 added to each standard solution before diluting with distilled water? What will be the resulting color of the solution and why is this the color that is observed?Q5/ Calculate the concentration of sodium ion in grams per liter after mixing 150mL of 0.200 M NaCl and 250ml of 0.250 M Na,S04. (20M) Atom weight = Na = 22.9897, Cl = 35.453, O = 16 H=1S = 32.065, Ca = 40.078 Ba = 137.327, C= 12.0107, N = 14.0067
- Calculate the mass percent of the ascorbic acid in the same show full solution Situation: The pounded Vitamin C tablet was half into two below are the calculated data in the experiment. Each of the half are transfered in a 250ml erlen meyer flask and added 75ml of deionized water for the vitamin C to dissolve. Then it was prepared for titration where the burette was filled with 0.09794M standardize NaOH solution then a total of with 3 drops 2% phenolphthalein indicator was added to each erlen meyer flask l, swrill it and begin the titration. below are the following data gathered: Vitamins used: Nature Made vitamin C 500mg tablet Trial 1 Mass: 0.3108g of Vitamin C tablet Initial volume: 1.6mL Final volume: 15.4mL Trial 2 Mass: 0.3349g Initial volume: 15.4 mL Final volume: 30.2 mLA 20.0 mL sample was analyzed using the Mohr method. Calculate the percent (w/v) CI (FM = 35.45) if 25.00 mL of 0.1234 M AgNO3 was used to form the yellow-orange endpoint. O 35.9% O 5.47% O 2.19% O 0.547%A 1 mL microbial suspension comparable to 1 mL of 1.0 McFarland standard was subjected to a series of dilutions. An aliquot of 0.2 mL was transferred into a 100-mL volumetric flask and diluted with sterile saline solution to its final volume. Then a 0.1 mL of the resulting solution was transferred into a 50-mL volumetric flask diluted to its final volume. What would be the final concentration?
- 1. A sample of an infusion was diluted 10 ml to 250 ml and then 10 ml to 200 ml. It was then analysed and was found to contain sodium at 0.789 mg/100 ml. Calculate the concentration of sodium in the original sample in %w/v. The sample was composed of a mixture of sodium lactate and sodium carbonate in equimolar amounts. Calculate the amount of sodium lactate and sodium carbonate in mg/10 ml of the sample (Na = 23, lactate = 89, carbonate = 60) 2. 0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity. What is the level of impurity in % w/w and ppm? 3. Calculate the pH of a buffer system made by dissolving 1.2 g of acetic acid and 0.82 g of sodium acetate in 500 ml of distilled water (pKa of acetic acid = 4.7) 4. Convert the following concentrations into the required expression. Concentration given Expression required 0.5% NaCl molarity 1 mM of KBr…A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The following results were obtained. (See attached image)(a) Calculate the mean w/v percentage of acetic acid in the sample.(b) Calculate the standard deviation for the results.(c) Calculate the 90% confidence interval for the mean.(d) (d) At the 90% confidence level, could any of the results be discarded?A sample of anhydrous NaHCO3 (FM = 84.007) is suspected to be contaminated with eitherNaOH (FM = 39.997) or Na2CO3 (FM = 105.989). To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using double flask method. If the sample requires 0.45 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and 35.95 mL to reach the bromcresol green endpoint, calculate the percentage composition (in %w/w) of all the basic components in the sample.