A voltage V= 300 cos 100 t is applied to a half wave rectifier, with RL =5K2, Calculate the DC Power a. 0.8W b. 1.814W c. 18.14W d. 1.5 W A voltage V= 300 cos 100 t is applied to a half wave rectifier, with RL =5KN, Calculate the Rectifier efficiency a. 0.40% b. 40.4% C. 40% d. 40.31 %

A voltage V= 300 cos 100 t is applied to a half wave rectifier, with RL =5K2, Calculate the DC Power a. 0.8W b. 1.814W c. 18.14W d. 1.5 W A voltage V= 300 cos 100 t is applied to a half wave rectifier, with RL =5KN, Calculate the Rectifier efficiency a. 0.40% b. 40.4% C. 40% d. 40.31 %

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter30: Dc Motors

Section: Chapter Questions

Problem 6RQ: What is CEMF?

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Question

100%

A voltage V= 300 cos 100 t is applied to a half wave
rectifier, with RL =5KN,
Calculate the DC Power
a. 0.8W
b. 1.814W
c. 18.14W
d. 1.5 W
A voltage V= 300 cos 100 t is applied to a half wave
rectifier, with RL =5KN,
Calculate the Rectifier efficiency
a. 0.40%
b. 40.4%
C. 40%
d. 40.31 %
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