For the full wave rectifier circuit shown in Figure 2, calculate: 1) The maximum current thro ugh the load. Vrms = 280v 2) The average current through the load. Vin R,= 12K2 1. = 280v Vrms 3) The average voltage across the load. 4) The rms value of the current. 5) The rectification efficiency. Figure 2
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- A half-wave rectifier is to provide an averagevoltage of 50 V at its output.a. Draw a schematic diagram of the circuit.b. Sketch the output voltage waveshape.c. Determine the peak value of the output voltage. d. Sketch the input voltage waveshape.e. What is the rms voltage at the input?a) Explain the operation of the controlled full-wave bridge rectifier shown in figure 3. b) The controlled full-wave bridge rectifier shown in figure 3 has a source 120 V rms at 60 Hz, R = 1092, L=20 mH, and a = 60°. Determine: i. An expression for the load current. ii. The average load current. iii. The power absorbed by the load. iv. Sketch the graph of the output waveform. Vs S₁ S4 Figure $3 $₂ Lo Vo1) In a single half wave rectifier which is uncontrolled, with an input voltage of 240V, 50HZ with a load of pure resistance of 1502 connected. Apply the core concepts of uncontrolled rectification to solve the following parameters a) Average and rms value of output voltage across the load b) Aveage and rms value of output current c) Average value of ac power across the load d) Power factor e) Ripple factor
- Calculate the rms load current for the single phase uncontrolled half-wave rectifier when the source voltage of 200V at a frequency of 50Hz, and load resistance is 10ohm.For a full wave controlled rectifier with pure resistive load (R=100),the supply voltage is (V-50Sin314t). When the firing angle (a =0%) determine the followings: 1) The mean (dc) value of the load current. 2) The RMS value of the load voltage.Design a single-phase full wave bridge rectifier with input voltage of 100v and inductive load of 10ohm and 40mH a. Show the waveform relation between the I/P and O/P b. Calculate the average O/P voltage c. Calculate the rms current
- A R-load half-wave rectifier used sinusoidal voltage source with a peak value (35.353kV). The firing angle is (30). The total resistance is 50k2 and frequency is 50HZ. Calculate (in details): load direct voltage, maximum direct voltage, normalized voltage and effective voltage, power delivered to the load, power factor, form factor, ripple factor?Which of the following statements about bridge tip rectifiers is false? A) If the 1-phase type has source inductance, the average value of the output voltage is lower than in the absence of the inductance. B) The average output voltage value of the 1-phase type is 0.9 times the peak voltage of the network. C) none D) There are only odd harmonics in the current drawn by the 1-phase type from the mains. E) The average value of the output voltage of the 3-phase type is larger as the 3-phase and 1-phase types are comparedH.W:- For a single phase half wave uncontrolled rectifier if the input supply voltage is (v= 310 sin314t), at frequency (f= 50 Hz). Then determine the followings:- Vm. Vmean- i. Draw the rectifier circuit. un %3D ii. Draw the input and the output voltages waveforms. iii. Determine the mean and rms values of the output voltage. s Ec iv. If the load is (R=10 S), then determine the mean and rms values of the current. 2019
- A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consisting series connected a resistor and an inductance from a 70.7V (RMS), 50HZ sinusoidal AC source. The firing delay of the thyristor is 90° and the load values are R=10Q, L=0.1 H. Define the load current expression and draw the load current by calculating for first two periods. And calculate the average values of the load voltage and current.1.) The voltage on Figure Q1 is connected across a 0.15 2 resistive load. Calculate the power dissipated in this resistor. 2.) A 12 V rms ac supply is connected to the primary winding of a transformer with a turns ratio of 0.052. Calculate the rms secondary voltage given a voltage regulation of 4.0% 3.)Sketch the circuit for an ac supply input to a full-wave diode rectifier with a resistive load and no smoothing capacitor.iii. For fully controlled single phase bridge rectifier with inductive load (load current is continuous) ,supply voltage 220 V(RMS) and a=30° .The mean value of output voltage is : (a) 150.32V (b) 171.52V (c) 120.98V