A tall plant with red flowers (dominant) is crossed with a dwarf plant with white flowers (recessive). Work out a dihybrid cross and state the dihybrid ratio. What will be the effect on the dihybrid ratio if the two genes are interacting with each other?
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A tall plant with red flowers (dominant) is crossed with a dwarf plant with white flowers (recessive). Work out a dihybrid cross and state the dihybrid ratio. What will be the effect on the dihybrid ratio if the two genes are interacting with each other?
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- For the following cross, show the P generation Genotypes and the Phenotypic ratio that would be seen in the F1 and F2. Remember, to produce the F2 generation you want to cross Heterozygotes from the F1. d) Genes 1 and 2 exhibit Epistasis (9:6:1) and Gene 3 is an Autosomal Dominant. In the P generation, the Male is Homozygous Recessive for the Genes showing Epistasis. Use E1, E2 and E3 to represent the Phenotypes shown by Epistasis. Report your results in the following format: P = aabb x AABB, F1 = 100%AaBb (Phenotype), and %3! F2 = 9/16 A_B_ (Phenotype), 3/16 aaB (Phenotype), 3/16 A_bb (Phenotype), 1/16 aabb (Phenotype)In sweet pea, gene C or P alone produces white flowers, the purple color being due to the presence of both of these factors. A white-flowered plant crossed with a purple produces progeny of which 3/8 are purple and 5/8 are white-flowered plants. Give the genotypes of the parents and offspring.Diagram the P1 and F1 crosses, using Mendelian notation, to show the possible genotypes found in each generation. (Remember a diagram is just the cross itself, not the progeny).
- In sweet peas, gene C or P alone produces white flowers, the purple colour being due to the presence of both these factors. What will be the flower colour of the offsprings of the following crosses, in which genotypes of parents are given;a) A white flowered plant crossed with a purple produces offspring, of which three-eighth are purple and five-eighth white.Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w) and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white eyes traits. The cross was carried to an F2 progeny and only male offspring were tallied. Based on the data shown here, a genetic map was constructed. a) Diagram the genotypes of the F1 parents. b) Construct a map, assuming the white is at locus 1.5 on the X-chromosome. Phenotype Male offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w) and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white eyes traits. The cross was carried to an F2 progeny and only male offspring were tallied. Based on the data shown here, a genetic map was constructed. a) Diagram the genotypes of the F1 parents. b) Construct a map, assuming the white is at locus 1.5 on the X-chromosome *******ANSWER PART B NOT PART A!!!! Phenotype Male offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0
- In a two factor cross, the longest possible map distance is 50 map units. Explain why this is true. How then can genetic maps show two genes that are 70 map units or more apart?Fruit fly body color is wild type (meaning normal) Gray = B+ and black = b Fruit fly wing type is wild type normal wings = vg+ and vg = vestigial A fly which was heterozygous for both traits was crossed with a fly that was recessive for both traits. Write the genotype and phenotype that would be expected from this cross. Write the genotype and phenotype percentages that would be expected from this cross.In poultry , the genotype-phenotype relationship for comb shape are R/-P/-, walnut. R/-p/p rose, r/rP/-,pea and r/r/p/p single.what will be the following crosses? a)A rose rose crossed with a walnut produces offspring that are walnut ,rose,pea and single. b)A rose crossed with a pea produces five walnut and six rose offspring. c) A walnut crossed with a walnut produces one rose two walnut and one single offspring.
- Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data shown here, a genetic map was constructed. Phenotype Male Offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0 (a) Diagram the genotypes of the F1 parents. (b) Construct a map, assuming that white is at locus 1.5 on the X chromosome. (c) Were any double-crossover offspring expected? (d) Could the F2 female offspring be used to construct the map? Why or why not?J.W. McKay crossed a stock (true-breeding) melon plant that produced tan seeds with a plant that only produced red seeds and obtained the following results (J.W. McKay. 1936. Journal of Heredity 27:110-112). Cross F1 F2 Tan x red 13 tan 93 tan, 24 red a) Explain the inheritance of tan seeds and red seeds in this plant. b) Assign symbols for the alleles in this cross and draw out the Punnett Squares for the initial cross and the F1 cross.In rabbits, an allelic series helps determine coat color. The alleles, in order of dominance, are listed below. C=full coat color Cch-chinchilla Ch-himalayan c=white What is the predicted outcome for a CCh rabbit crossed with a Cchc rabbit? Draw out the cross and show the predicted genotypes and phenotypes for the offspring.