A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship; folded(F) = unfolded (U), k=[U]/[F] For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation: ∆GO=RTlnk=-2.3RTlog k, where R=1.98 x 10-3kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship; folded(F) = unfolded (U), k=[U]/[F] For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation: ∆GO=RTlnk=-2.3RTlog k, where R=1.98 x 10-3kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 119QRT
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A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship;
folded(F) = unfolded (U), k=[U]/[F]
For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation:
∆GO=RTlnk=-2.3RTlog k,
where R=1.98 x 10-3kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
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