5. The color of the hull in oat seeds are determined by two genes that independently assort. The black hullphenotype is due to a dominant allele A. The grey hull phenotype is due to a dominant allele B. However,the effect of B is only apparent in the aa genotypes. In other words, the presence of the A allele masks theeffect of the genotypes in the B gene. If neither A or B is present, the color of the hull would be white.You take a true breeding white strain (aabb) and cross it with a true breeding black strain (AABB). You letthe F1 generation self-fertilize and collected the F2 generation of seeds.a. In the diagram below, please fill out the blue areas. In the rectangles, please fill in genotypes. In theparentheses, fill in proportions of respective genotypes. In the lines, specify the respective phenotypes(black, grey or white)..b. Out of all the black hulled seeds, what proportions have the genotype AaBb? Please show allcalculations..yourPOF1F2(A_B_AABB(aaB()(A_bbaabb)aabb

a. In the diagram below, please fill out the blue areas. In the rectangles, please fill in…

Answered: 5. The color of the hull in oat seeds…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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1. Alleles of the gene that determines seed coat patternsin lentils can be organized in a dominance series:marbled > spotted = dotted (codominant alleles) >clear. A lentil plant homozygous for the marbled seedcoat pattern allele was crossed to one homozygous forthe spotted pattern allele. In another cross, a homozygous dotted lentil plant was crossed to one homozygous for clear. An F1 plant from the first cross wasthen mated to an F1 plant from the second cross.a. What phenotypes in what proportions are expectedfrom this mating between the two F1 types?b. What are the expected phenotypes of the F1 plantsfrom the two original parental crosses?
9. In the F2 Generation, both the male and female pea plants are heterozygous for round/wrinkles seeds. 1)Draw a Punnett square that shows this cross. 2)What are the possible genotypes? 3)What are the possible phenotypes? 10. In pea plants, the allele for smooth pods (P) is dominant over the allele for pinched pods (p). Construct a Punnett Square that shows a cross between an PP plant and an Pp plant. Predict what percent of the offspring are likely to have smooth pods. Essay: Is it possible for a son to inherit an allele on an X chromosome from his father? Explain why or why not.
1. In guinea pigs, two different genes affect the coat. One gene codes for coat color and there are 2 codominant alleles C1=Brown and C2=White. The heterozygous form is tan colored. The second gene codes for presence of hair with H=hairy (dominant) and h=hairless (recessive). If we didn't know the genotypes of the parents, but mom is hairless and dad is tan haired, and the babies produced included brown, tan, white, and hairless, can you guess the genotypes of the parents? Show your work below (explain how you came up with the answers)
2. Two unlinked loci effect mouse hair color. CC or Cc mice are agouti. Mice with genotype cc are albino because all pigment production and deposition of pigment in hair is blocked. At the second locus, the B allele (black agouti coat) is dominant to the b allele (brown agouti coat). A mouse with a black agouti coat is mated with an albino mouse of genotype bbcc. Half of the offspring are albino, one quarter are black agouti, and one quarter are brown agouti. What is the genotype of the black agouti parent?
8. Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white AAbb x AaBb AABb x Aabb aaBb x Aabb AABb x aabb AABb x AaBb A wheat plant producing medium red seed is crossed with another plant producing intermediate red seed (refer to problem no. 8). How many individuals will be? Red Medium red Intermediate red Light red White
13. In another species of berry, Rass berrylis, the allele for yellow fruit (F) is dominant to the allele for red fruit (f), and the allele for thorny stems (T) is dominant to the allele for thornless stems (t). The gene for fruit colour is 17.4 map units from the stem thorniness. gene for a. Draw a Punnett square to illustrate the cross between a Rass b. with red berries and thornless stems and a plant that was heterozygous for both characteristics. (The parents of the heterozygous plant were yellow-fruiting and thorny, and red- fruiting and thornless, and were homozygous for both traits.)
3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?
1. Two loci found in mice are suspected to be linked. To test this hypothesis, a group of graduate students performed a test cross between mice that are true breeding for both dominant traits and mice that are true breeding for both recessive traits. Individuals from the F1 generation were crossed with individuals that express both recessive traits. The phenotypic results are shown in the table below. Use chi-square analysis to determine if the graduate students’ hypothesis is supported by the evidence. Phenotype Number of OffspringDominant 1, Recessive 2 132Dominant 1, Dominant 2 128Recessive 1, Recessive 2 118Recessive 1, Dominant 2 124 a. What are the degrees of freedom and the critical chi-square value (from the table)?b. What is the calculated chi-square value?c. Do the results support that the loci are linked or that they are independently assorted (unlinked)?
10. In pea plants, seed shape and seed color are controlled by genes located on different chromosomes. Seeds may be round (R) or wrinkled (r), with the allele for round seeds being dominant. Alleles for seed color are yellow and green, with the green allele (y) recessive to the yellow (Y) allele. If you cross an individual that is homozygous round and yellow with an individual that is homozygous for wrinkled and green, what is the genotype of the F1 individuals? Set up a Punnett square for the dihybrid cross.
6. Suppose two independently assorting genes are involved in the pathway that determines color in squash. These genes interact with each other to produce the squash colors seen in the grocery store. At the first locus, the W allele codes for a dominant white phenotype, whereas the w allele codes for a colored squash. At the second locus, the allele G codes for a dominant yellow phenotype, and the allele g codes for a recessive green phenotype. The phenotypes from the first locus will always mask the phenotype produced by the second locus if the dominant allele (W) is present at the first locus. This masking pattern is known as dominant epistasis. a. A dihybrid squash (WwGg) is selfed and produces 160 offspring. How many offspring are expected have each of the following phenotypes? White: Yellow: Green: b. For the same squash species, what is the expected phenotype ratio for a cross of a green squash with a purebred yellow squash? c. For the same squash species, what is the expected…
6. In corn plants, a dominant allele I inhibits kernel color, while the recessive allele i permits color when homozygous. At a different locus, the dominant gene P causes purple kernel color while the homozygous recessive pp causes red kernels. If a plant that is heterozygous at both loci is crossed with a plant that has red kernels, what will be the phenotypic ratio of the offsprings?
3- Pigment in mouse fur is only produced when the C allele is present. Individuals of the cc genotype are white. If color is present, it may be determined by the Aa alleles. AA or Aa results in agouti color, while aa results in black coats, When a black female is crossed with a white male, all phenotypes are observed in the offspring. In this case, what should be the ratio of the black offsprings? a) 1/32 b) 1/16 70204 C) 1/4 d) 1/8 1/2 Boş bırak

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