3- Pigment in mouse fur is only produced when the C allele is present. Individuals of the cc genotype are white. If color is present, it may be determined by the Aa alleles. AA or Aa results in agouti color, while aa results in black coats. When a black female is crossed with a white male, all phenotypes are observed in the offspring. In this case, what should be the ratio of the black offsprings? a) 1/32 b) 1/16 C) d) e) 1/2 1/4 70204 1/8 Boş bırak

3- Pigment in mouse fur is only produced when the C allele is present. Individuals of the cc genotype are white. If color is present, it may be determined by the Aa alleles. AA or Aa results in agouti color, while aa results in black coats. When a black female is crossed with a white male, all phenotypes are observed in the offspring. In this case, what should be the ratio of the black offsprings? a) 1/32 b) 1/16 C) d) e) 1/2 1/4 70204 1/8 Boş bırak

Name: 3- Pigment in mouse fur is only produced when the C allele is present
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Description: 3- Pigment in mouse fur is only produced when the C allele is present. Individuals of the cc genotype are white. If coloris present, it may be determined by the Aa alleles. AA or Aa results in agouti color, while aa results in black coats,When a bla

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter13: Modern Understandings Of Inheritance

Section: Chapter Questions

Problem 2VCQ: Figure 13.4 Which of the following statements is true? Recombination of the body color and red/...

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31 1. In guinea pig, fur color is determined by one gene, and fur length by another independently segregating gene. The black fur allele (B) is dominant to brown fur allele (b) and the short allele (S) is dominant to long fur allele (s). From progeny listed in the following table, provide the probable genotype for the parents of each cross. Phenotype of Progeny Black short black long brown short Bio3110 Genetics Additional problems (Chapter 2): Parents Black short X Black short Black short X Brown long Black long X Black long 90 17 0 32 16 35 29 14 0 brown long 8 15 2. A mouse with the genotype BbccEeFf is mated with another mouse with BBCcEEFF genotype. What is the probability of obtaining the following genotype in the progeny? a. BBCcEeFF b. BbccEEFf C. BbccEeFF 12 3. Determine the type of gametes that are formed from the following individuals with the given genotype? A. AaBbCc B. AABBCc C. AABbCc
3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?
7. In the guinea pig, one locus involved in the control of coat color may be occupied by any of four alleles: C (full color), ck (sepia), cd (cream), or c (albino), with an order of dominance of: C>ck > cd > c. In the following crosses, determine the parental genotypes and predict the phenotypic ratios that would result. a) Sepia x cream, where both guinea pigs had an albino parent b) Sepia x cream, where the sepia guinea pig had an albino parent and the cream guinea pig had two sepia parents c) Sepia x cream, where the sepia guinea pig had two full color parents and the cream guinea pig had two sepia parents d) Sepia x cream, where the sepia guinea pig had a full color parent and an albino parent and the cream guinea pig had two full color parents.
9. Please determine whether the allele responsible for the trait is dominant or recessive. (A) (B) 1 2 10.For a cross between a female color blind carrier and a male color blind person, what is the probability for the female offspring to be color blind? What is the probability for the male offspring to be color blind? Please explain. 11.Consider the genetic map shown below AD Which two alleles have the highest recombination frequency? Which two have the lowest recombination frequency? O Focus ! 72°F DELL F5 F6 PrtScr Insert Hor FZ F8 F9 F10 F11 F12 23 %24 3. 4. 8 E R T
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?
5. In cattle, roan color (mixed red and white hairs) occurs in the heterozygous (Rr) offspring of red (RR) and white (rr) homozygotes. When two roan cattle are crossed, the phenotypes of the offspring are found to be in the ratio of 1 red: 2 roan: 1 white. a) What cross could produce the highest percentage of roan cattle? b) How would one produce a herd of pure-breeding roan-color cattle? Explain
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratio
Genetic Crosses that Involve 2 Traits In rabbits, black hair is dominant to brown hair. Also in rabbits, long straight ears are dominant to floppy ears. These letters represent the genotypes and phenotypes of the rabbits: BB = black hair EE = long ears Ee = long ears ee = floppy ears %3D %3D Bb = black hair bb = brown 1. A male rabbit with the genotype BBee is crossed with a female rabbit with the genotype bbEe The square Is set up below. Fill it out and determine the phenotypes and proportions in the offspring. How many out of 16 have black hair Ве Ве Ве Ве and long ears? bE How many out of 16 have black hair and floppy ears? be How many out of 16 have brown hair and long ears? bE How many out of 16 have brown hair be and floppy ears?
1-Show the results of a dihybrid cross for the F1 and F2 generation between P generation of a pea plant that is homozygous dominant for purple flower and yellow pea seed with another pea plant that is homozygous recessive for white flower and green pea seed. Clearly show the cross indicating BOTH genotype and phenotype for each generation. How many offspring in the F2 generation will have these phenotypes? 2-What is the probability of a woman who is a carrier for the blood disease hemophilia producing a son with hemophilia if she marries a man who does not have hemophilia? What is the probability of her daughters having hemophilia? Explain why the probability of getting this disease is different for sons versus daughters in this case. Your work should clearly indicated sex, genotype and phenotype (carrier or affected).
3. The gene that controls coat colour in rabbits has four alleles: agouti (C), chinchilla (cck), Himalayan (ch), and albino (c). The order of dominance among these alleles is C> cch > ch > c. A) heterozygous Himalayan rabbit is crossed with a chinchilla rabbit that had an albino father. a) What are the genotypes of the two rabbits? a Punnett square determine the phenotypic ratio of the rabbits’ offspring.
9. In fruit flies, the gene for tan body color (T) is completely dominant over the gene for ebony body color (t). The gene for red eyes is dominant over the gene for white eyes and is a sex-linked trait. A tan female with red eyes (heterozygous for both traits) is crossed with a homozygous ebony male with white eyes. A) Write out the genotypes of two parents. Remember that eye color is sex- linked! Female: Male: B) Set up and fill out a punnett square for this cross. C) What is the probability of producing a fly that is an ebony male with white eyes?