4000 100 80 IR Spectrum (liquid film) 20 % of base peak 10 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) 3000 75 Live 101 M** 132 80 DEPT CH₂ CH₂ CH proton decoupled 5.0 ¹H NMR Spectrum (400 MHz, CDCI, solution) expansion 9 200 4.5 ppm 8 1715 2000 3.5 v (cm¹) 120 160 200 m/e 160 1600 7 3.0 120 expansion 6 1200 2.5 Mass Spectrum 800 ppm 240 280 5 C6H12O3 solvent 80 4 No significant UV absorption above 220 nm 3 40 Irt 2 0 1 8 (ppm) TMS 0 8 (ppm)
4000 100 80 IR Spectrum (liquid film) 20 % of base peak 10 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) 3000 75 Live 101 M** 132 80 DEPT CH₂ CH₂ CH proton decoupled 5.0 ¹H NMR Spectrum (400 MHz, CDCI, solution) expansion 9 200 4.5 ppm 8 1715 2000 3.5 v (cm¹) 120 160 200 m/e 160 1600 7 3.0 120 expansion 6 1200 2.5 Mass Spectrum 800 ppm 240 280 5 C6H12O3 solvent 80 4 No significant UV absorption above 220 nm 3 40 Irt 2 0 1 8 (ppm) TMS 0 8 (ppm)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Given the following NMR data, find the unknown compound.
a. Identify the molecular formula; find IHD
b. Identify the 1H and 13C NMR signals
Transcribed Image Text:4000
100
80
60
IR Spectrum
(liquid film)
40
20
% of base peak
43
75
LLL
40
13C NMR Spectrum
(100.0 MHz, CDCI, solution)
10
3000
proton decoupled
expansion
DEPT CH₂ CH₂ CH
¹H NMR Spectrum
(400 MHz, CDCI, solution)
5.0
200
1
9
80 120 160
m/e
4.5 ppm
www
L
8
2000
v (cm¹)
101 M**
132
3.5
1715
160
7
1600
3.0
120
expansion
6
1200
200 240 280
Mass Spectrum
2.5 ppm
800
10
5
C6H12O3
solvent
80
4
3
No significant UV
absorption above 220 nm
40
2
IN
0
1
8 (ppm)
TMS
0
8 (ppm)
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