-·|·4.0Match the peaks in this spectrum with hydrogens on the structure below.A)I: 0.91 ppmII:3.29 ppmIII:1.52 ppmIV: 3.23 ppmH3C|3.0||H₂CH3CHCH3III IV2.0ppm1.0B)I: 0.91 ppmII:3.29 ppmIII: 3.23 ppmIV: 1.52 ppmC)1:3.23 ppmII: 3.29 ppm+

For the given molecule, we have to select the correct match for the peaks in the spectrum

4.0 Match the peaks in this spectrum with hydrogens on the structure below. A) I: 0.91 ppm II: 3.29 ppm III: 1.52 ppm IV: 3.23 ppm H3C I 3.0 || of CH3 CH CH3 III IV 2.0 ppm 1.0 B) I: 0.91 ppm II: 3.29 ppm III: 3.23 ppm IV: 1.52 ppm G 3.23 ppm II: 3.29 ppm

4.0 Match the peaks in this spectrum with hydrogens on the structure below. A) I: 0.91 ppm II: 3.29 ppm III: 1.52 ppm IV: 3.23 ppm H3C I 3.0 || of CH3 CH CH3 III IV 2.0 ppm 1.0 B) I: 0.91 ppm II: 3.29 ppm III: 3.23 ppm IV: 1.52 ppm G 3.23 ppm II: 3.29 ppm

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter17: Applications Of Infrared Spectrometry

Section: Chapter Questions

Problem 17.5QAP

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

100%

-·|·
4.0
Match the peaks in this spectrum with hydrogens on the structure below.
A)
I: 0.91 ppm
II:
3.29 ppm
III:
1.52 ppm
IV: 3.23 ppm
H3C
|
3.0
||
H₂
CH3
CH
CH3
III IV
2.0
ppm
1.0
B)
I: 0.91 ppm
II:
3.29 ppm
III: 3.23 ppm
IV: 1.52 ppm
C)
1:
3.23 ppm
II: 3.29 ppm
+

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