Homework Help is Here – Start Your Trial Now!
Engineering
Data Structures and Algorithms
36 /** Returns the number of times second array stores sum of prefix sums from first. / 37. public static int example5(int[] first, int[] second) {// assume equal-length arrays 38 int n= first.length, count = 0; 39 for (int i=0; i

36 /** Returns the number of times second array stores sum of prefix sums from first. / 37. public static int example5(int[] first, int[] second) {// assume equal-length arrays 38 int n= first.length, count = 0; 39 for (int i=0; i

icon
Related questions
Question
100%
time complexity and space complexity
36 /** Returns the number of times second array stores sum of prefix sums from first. / 37 public static int example5(int[] first, int[] second) { // assume equal-length arrays int n= first.length, count = 0; // loop from 0 to n-1 for (int i=0; i<n: i++) { int total = 0; 59 993990 38 39 40 42 43 45 46 for (int jm0; j<n; j++) for (int km0; k<-j; k++) total + first[k]: if (secondi] total) count++; ) return count; ste // loop from 0 to n-1 // loop from 0 to j
Transcribed Image Text:36 /** Returns the number of times second array stores sum of prefix sums from first. / 37 public static int example5(int[] first, int[] second) { // assume equal-length arrays int n= first.length, count = 0; // loop from 0 to n-1 for (int i=0; i<n: i++) { int total = 0; 59 993990 38 39 40 42 43 45 46 for (int jm0; j<n; j++) for (int km0; k<-j; k++) total + first[k]: if (secondi] total) count++; ) return count; ste // loop from 0 to n-1 // loop from 0 to j
Expert Solution
steps

Step by step

Solved in 4 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer