Suppose you compute using the algorithm for modular exponentiation discussed in lecture and shown below: modExp (b, n, m): x = 1 01 P = b mod m for i = 0: k-1: 11 return x 121 Recall that, the algorithm assumes we know or can find the binary expansion of n so that n = (ak-1, ak-2,..., ao)2. If the initial values are x and p are 1 and 11 respective the possible values that x will attain at some iteration of the algorithm. 451 221 if a_i = 1: 226 391 x = (xp) mod m P = (pp) mod m 11644 mod 645
Suppose you compute using the algorithm for modular exponentiation discussed in lecture and shown below: modExp (b, n, m): x = 1 01 P = b mod m for i = 0: k-1: 11 return x 121 Recall that, the algorithm assumes we know or can find the binary expansion of n so that n = (ak-1, ak-2,..., ao)2. If the initial values are x and p are 1 and 11 respective the possible values that x will attain at some iteration of the algorithm. 451 221 if a_i = 1: 226 391 x = (xp) mod m P = (pp) mod m 11644 mod 645
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Transcribed Image Text:Suppose you compute
using the algorithm for modular exponentiation discussed in lecture and shown below:
modExp (b, n, m):
x = 1
01
0 0 0 0 0
P = b mod m
for i = 0: k-1:
11
return x
121
Recall that, the algorithm assumes we know or can find the binary expansion of n so that n = (ak-1, ak-2, ..., ao)2. If the initial values are x and p are 1 and 11 respectively, se
the possible values that x will attain at some iteration of the algorithm.
451
221
if
226
391
a i = 1:
x = (xp) mod m
P = (pp) mod m
11644 mod 645
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