I need help understanding how A is the correct answer for problem 21 and B is the correct answer for problem 22. Please explain to me the procedure to get these answers. Thank you. 21. A How many total cubic yards of coarse aggregate would be required to produce 150 yd³ of concrete ifthe coarse aggregate has a nominal size of 2.0 inch and a Fineness Modulus of 2.90?A. 110C. 75B. 0.734.73D. 15022. If 280 lb/yd of water is used in an air-entrained concrete mix with a coarse aggregate having a nominalaggregate size of 0.75 inches, which of the following would most likely to be the slump of the concrete?A. zeroC. 3.5 inchB. 1.5 inchD. 6.5 inchRelevant Tables and Equations:TABLE 7.5 Bulk Volume of Coarse Aggregate per Unit Volume of Concrete*Nominal MaximumSize of Aggregate,mm (in.)9.5 (3/8)12.5 (1/2)19 (3/4)25 (1)37.5 (1¹)50 (2)75 (3)150 (6)Slump, mm (in.)25 to 50(1 to 2)75 to 100(3 to 4)Bulk Volume of Dry-Rodded Coarse AggregatePer Unit Volume of Concrete for DifferentFineness Moduli of Fine Aggregate**Fineness Modulus150 to 175(6 to 7)2.400.500.660.710.750.780.829.5 (207 (350)228 (385)243 (410)2.60101 (905i0.480.690.730.7612.5 (¹)199 (335)216 (365)228 (385)2.80125 (205)0.550.820.710.780.83TABLE 7.8 Approximats Mixing Water in kg/m³ (b/yd) for Different Slumps and Nominal Maximum Aggregate Sizes190 (315)205 (340)3.00216 (360)0.440.530.600.650.690.720.760.81168 (270)%Vs193 (325)202 (340)Nominal Maximum Aggregate Size in mm (in.)**19 (J50 (2)***25 (1) 37.5 (1)Non-air-entrained concrete179 (300)166 (275)=n≥30 & s <500 psin230 & s≥ 500 psiYb (100)# samples (n)30252015<15GęXYwSpecifiedCompressive Strength1 MPa (psi)<21 (<3000)21 to 35 (3000 to 5000)>35 (>5000)(181 (300)190 (315)Air-entrained concrete160 (270)150 (250)154 (260)169 (285)178 (300)142 (240)for = f + 1.34sfor = f +2.33s-500Yo =Modification factor (F)1.001.0375 (3)***W solidV₁Required AverageCompressive Strengthfor MPa (psi)130 (220)f+7.0 (+1000)+8.5 (+1200)+10.0 (fe + 1400)100 (270)122 (205)1.081.16(see table below)conc150 (6)***145 (245) 124 (210)113 (190)10711801

Problem 21 : Data given Concrete to be produced = 150 yd3 Nominal size of coarse aggregates = 2…

21. How many total cubic yards of coarse aggregate would be required to produce 150 yd³ of concrete if the coarse aggregate has a nominal size of 2.0 inch and a Fineness Modulus of 2.90? A. 110 C. 75 73 B. 0.73 D. 150 2.B 22. conc If 280 lb/yd³ of water is used in an air-entrained concrete mix with a coarse aggregate having a nominal aggregate size of 0.75 inches, which of the following would most likely to be the slump of the concrete? A. zero C. 3.5 inch B. 1.5 inch D. 6.5 inch

21. How many total cubic yards of coarse aggregate would be required to produce 150 yd³ of concrete if the coarse aggregate has a nominal size of 2.0 inch and a Fineness Modulus of 2.90? A. 110 C. 75 73 B. 0.73 D. 150 2.B 22. conc If 280 lb/yd³ of water is used in an air-entrained concrete mix with a coarse aggregate having a nominal aggregate size of 0.75 inches, which of the following would most likely to be the slump of the concrete? A. zero C. 3.5 inch B. 1.5 inch D. 6.5 inch

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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