20 ml of 0.02 M sodium bicarbonate solution from a 2 M stock solution = C1 x V1 = C2 xV2 = (2 MV1) = (0.02) (20 mL) =V1 = 0.4 mL/2M = 0.2 mL Therefore, the student must add 0.2 mL of solution to water using the

Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.107E
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20 ml of 0.02 M sodium bicarbonate solution from a 2 M stock solution
= C1 x V1 = C2 xV2
= (2 MV1) = (0.02) (20 mL)
=V1 = 0.4 mL/2M
= 0.2 mL
Therefore, the student must add 0.2 mL of solution to water using the
Transcribed Image Text:20 ml of 0.02 M sodium bicarbonate solution from a 2 M stock solution = C1 x V1 = C2 xV2 = (2 MV1) = (0.02) (20 mL) =V1 = 0.4 mL/2M = 0.2 mL Therefore, the student must add 0.2 mL of solution to water using the
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