15. Hair color in trolls is controlled by a single gene. Assume blue hair (B) is dominant to green hair (b). Which of the following would have green hair? 1. BB 2. bb 3. Bb 4. Both BB and Bb
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- 11. Blood type is controlled by a gene with multiple alleles. A produces type A blood. B codes for type B blood. A and B are codominant so a heterozygote has type AB blood. The O allele is recessive to both A and B and produces type O blood. A. What are the possible genotypes of a man with type A blood? B. What are the possible genotypes of a man with type B blood? C. Can a man with type B blood be the father of a baby with type O blood? Why or why not? Explain your answer. D. A man with type A blood marries a woman with type B blood. What blood types are possible for their children? Explain your answer. E. A man with type O blood is in a car accident and has to receive a transfusion at the hospital. What types of blood can he receive? F. In the Charlie Chaplin paternity case of the 1940s, a young woman sued Chaplin for child support, claiming he was the father of her child. Chaplin’s blood was type O, the mother was type A and the baby was type B. Could…11. Blood type is controlled by a gene with multiple alleles. A produces type A blood. B codes for type B blood. A and B are codominant so a heterozygote has type AB blood. The O allele is recessive to both A and B and produces type O blood. A. What are the possible genotypes of a man with type A blood? B. What are the possible genotypes of a man with type B blood? C. Can a man with type B blood be the father of a baby with type O blood? Why or why not? Explain your answer. D. A man with type A blood marries a woman with type B blood. What blood types are possible for their children? Explain your answer. E. A man with type O blood is in a car accident and has to receive a transfusion at the hospital. What types of blood can he receive? F. In the Charlie Chaplin paternity case of the 1940s, a young woman sued Chaplin for child support, claiming he was the father of her child. Chaplin’s blood was type O, the mother was type A and the baby was type B. Could…4. In roan bulls, alleles for both red and white hair are codominant (BRBW). What is the percentage of genotype and phenotype if a roan cattle is bred to: (a) a homozygous red cow (BRBR) (b) a heterozygous white cow (BWBw)
- 7. While Squidward's family boasts about being a purebred line for dominant light blue skin color, they are also purebred for a less distinguished trait: the recessive trait of baldness. Lack of hair causes Squidward some self-esteem issues that he does not want his children to face. He would like to ensure that his offspring have hair AND with his blue skin color. What traits should he look for in a bride? A. Must she have hair? Explain. Squidward Traits: Skin Color B. Must she be blue? Explain. Blue = B, Green = b Hair Hair = H, Bald =h C. Squidward has found a potential bride prospect with the green squid Octavia. While Octavia has does not. Determine the chances of their child being blue and having hair. hair, her father Squidward's Genotype Octavia's Genotype = D. Use the genotypes in above to complete the Punnett square below and then answer the questions. E. Answer these questions based on your Punnett square. For which traits, if any, is it possible for their offspring to be…3. In humans, brown eye colour (B), is dominant over blue eye colour (b). a. What are the phenotypes of the following genotypes? In other words, what colour eyes will they have? BB bb Bb b. Tom is a brown-eyed man, whose mother is blue-eyed. He marries Freda, a blue eyed woman whose father has brown eyes. From this information, deduce: i. The genotypes of Tom and Freda ii. The genotypes of Tom's mother and Freda's father. iii. Given what you have deduced so far, what colour eyes would you predict Tom's father to have? iv. Tom's brother George has blue eyes. Using this additional information, deduce the genotype of their father. Ensure you explain your answers throughout.1. In humans, normal pigmentation is due to a dominant gene A. Albinism is due to the recessive allele a. A man without albinism marries an albino woman and their first child is an albino. What are the genotypes of these 3 people? a. Mother:b. Father:c. Child: 2. In humans, achondroplasia “dwarfism” (D) is dominant over normal (d). A homozygous dominant (DD) person dies before the age of one. A heterozygous (Dd) person is dwarfed. A homozygous recessive individual is normal. A heterozygous dwarf man marries a heterozygous dwarf woman… a. What is the probability of having a normal child?b. What is the probability that the next child will also be normal?c. What is the probability of having a child that is a dwarf? Define the following terms:1. Autosome:2. Sex chromosome:3. Carrier:
- 8. Huntington’s disease is a degenerative disease of the nervous system that strikes in middle age. The allele that causes the disease (H) is dominant to the allele that results in the normal condition (h). Answer the following questions about the inheritance of this disease. A. What is the genotype of a man who is normal but whose father had Huntington’s disease? B. What is the genotype of a woman who has Huntington’s disease if both of her parents had Huntington’s disease? C. If a man who is heterozygous for Huntington’s disease marries a woman who is normal, what would you expect for the genotypes and phenotypes of their children? D. If a normal man marries a woman who is homozygous for Huntington’s disease, what do you expect for the genotypes and phenotypes of their children?4. One parent is homozygous for the allele for myostatin that results in typical muscles and the other parent is heterozygous (mm x Mm) a. Part A (fill in the boxes): m m M b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%10. A cat with broad pigmented bands and whorls mates with a tabby cat heterozygous for the tabby gene. Their first kitten is albino. What is the probability that their next kitten will also be albino? [Choose ] [Choose ] 0.375 What is the probability that their next kitten 0.75 will be mackerel-striped? 0.625 0.33 0.5 0.25 0.875 1.0 <
- 7. It has long been known in the field of human genetics that wavy hair is the expression of a heterozygous genotype in which the allele for straight hair is paired with the allele for curly hair. Lucinda Lovelee married Larry Legg. Both of these charmers have wavy hair. What is the probability that their offspring, the littlest Legg, will have: a wavy hair? b. curly hair? C. straight hair?5. Assume that cat blood types are the same as human blood types. In the following blood type questions, even though the blood type may be given, the genotype is not. If you are not able to figure out the genotype, and there is more than one possibility, you must assume both possibilities are equally likely. Two points each. Show work. a) Arlene is blood type B. Her mate Garfield is blood type O. What blood type(s) of kittens might they have? b) Kitten Nermal's dad Crookshanks is type AB. Nermal's mom Mrs. Norris is type A, and Mrs. Norris' mother was type O. (Hint: figure out your Mrs. Norris' genotype first). What is the chance that Nermal's genotype is AA? c) Simba is blood type AB. His biological father Mufasa is blood type B. What blood type(s) could the mother Sarabi NOT have?2. One parent is homozygous for the allele for myostatin that results in big muscles and the other is homozygous for the allele that results in typical muscles (MM x mm). a. Part A (fill in the boxes): M M m m b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%