You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section: Chapter Questions
Problem 139SCQ: Two students titrate different samples of the same solution of HCl using 0.100 M NaOH solution and...
icon
Related questions
Question

Please don't provide handwritten solution ... 

You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with
approximately 200 mL of water. You now need to determine its precise concentration
and you have performed five titration trials to standardize your solution. Here are
the results of your trials:
trial # mass of potassium biphthalate (mg)
volume of NaOH solution (mL)
12.30 mL
1
180 mg
15.20 mL
2
180 mg
12.20 mL
3
180 mg
13.90 mL
4
180 mg
12.50 mL
5
180 mg
You now have to calculate the average molar concentration of your NaOH solution
and you want it to be as precise as possible. How are you going to do it?
I will only use trials 1 and 3
I will use all the trials for my calculations
I will discard trial 4
I will discard trials 2 and 4
Transcribed Image Text:You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
Recommended textbooks for you
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning