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y P1--- P3 0.50 m 10.50 m

y P1--- P3 0.50 m 10.50 m

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Question #3. The last person did the wrong number. Please use the attached equation sheet and start with an equation from the sheet and work from there. You can manipulate anyway you want you just have to start from the equation sheet.
SSM = solution in Student Companion & Problem-Solving Guide *= intermediate = challenging X = life science application 25.1 COHERENCE AND CONDITIONS FOR INTERFERENCE 1. Light waves are emitted coherently from two sources and detected at a spot equidistant from the two sources. Do these waves interfere constructively or destructively at this spot? P1 P3 2. Sound waves with a wavelength of 0.25 m are emitted coherently (i.e., in phase with each other) from two 0.50 m 10.50 m sources. These waves are found to interfere constructively at a point P that is 1.60 m from one of the sources. What is the distance from P to the other source? Note: There is more than one correct answer. Give three of them. a 0.50 m 3. Coherent sound waves with 1 = 0.75 m are emitted from points P, and P, in Figure P25.3. Do these 1r waves interfere constructively or destructively at point P3?oq brodb 'uing Figure P25.3 off CSU 0.29 m
Transcribed Image Text:SSM = solution in Student Companion & Problem-Solving Guide *= intermediate = challenging X = life science application 25.1 COHERENCE AND CONDITIONS FOR INTERFERENCE 1. Light waves are emitted coherently from two sources and detected at a spot equidistant from the two sources. Do these waves interfere constructively or destructively at this spot? P1 P3 2. Sound waves with a wavelength of 0.25 m are emitted coherently (i.e., in phase with each other) from two 0.50 m 10.50 m sources. These waves are found to interfere constructively at a point P that is 1.60 m from one of the sources. What is the distance from P to the other source? Note: There is more than one correct answer. Give three of them. a 0.50 m 3. Coherent sound waves with 1 = 0.75 m are emitted from points P, and P, in Figure P25.3. Do these 1r waves interfere constructively or destructively at point P3?oq brodb 'uing Figure P25.3 off CSU 0.29 m
MusH start w/one of These equahons V-3.0 X10 ps Air light: Use "v" for volume i no "L" use subscripts Physics 104 Equation Sheet Ho = 4n x 107 N/A? c = 3.00 x 10% m/s e = 1.6 x 10 19 C Eo = 8.85 x 10 12 C²/Nm² k = 9.0 x 10° Nm2/C² h = 6.63 x 10 34 Js = 4.14 x 1015 eVs lo = 1012 w/m2 me = 9.11 x 10 31 kg m, = 1.67 x 10 27 kg nwater = 1.33 1 eV = 1.6 x 1019 J nair = 1.00 nsoap = 1.50 Vsound = 340 m/s Wsilver = 4.74 eV AV = -EAx PE = kqı92/r V = kQ/r F = kqıq2/r? E = kQ/r? F = qE C = q/AV APEE = -WE = -qEd APE = qAV PE = ½ QAV C = E0A/d ReqΣ R 1/ Req Σ 1/R P = IAV AV = IR R = pL/A F = ILB sino F = qvB sino EMF = NA DB/At B = Hol/2nr B = Honl Os = BA cosO IV1 = 12 V2 V1/V2 = N1/N2 EMF = NBAW sin(wt) Frequencey. W = 2nf = f = 1/T F = -kAx V = fA n = c/v An = Aair/n m PE = ½ kAx? V = fs ni sino1 = n2 sinO2 relachiorine o 1/o + 1/i = 1/f fo = fo = fs(1 ± °o/p) d sino = mA B = 10 log10 (1/lo) 2/l1 = r?/r,? d sino = (m + ½ )A m = -i/o f = R/2 P = 1/f E = hf Am T = 2.90 x 10 mK KEmax = hf – W Rn = (0.0529 nm) n² A = h/mv = h/p A-N = (h/mc)(1 – cosO) En = -13.6eV/n? L = nh/2n AxAp, 2 h/47 ΔΕΔt h/4π Fomg sing
Transcribed Image Text:MusH start w/one of These equahons V-3.0 X10 ps Air light: Use "v" for volume i no "L" use subscripts Physics 104 Equation Sheet Ho = 4n x 107 N/A? c = 3.00 x 10% m/s e = 1.6 x 10 19 C Eo = 8.85 x 10 12 C²/Nm² k = 9.0 x 10° Nm2/C² h = 6.63 x 10 34 Js = 4.14 x 1015 eVs lo = 1012 w/m2 me = 9.11 x 10 31 kg m, = 1.67 x 10 27 kg nwater = 1.33 1 eV = 1.6 x 1019 J nair = 1.00 nsoap = 1.50 Vsound = 340 m/s Wsilver = 4.74 eV AV = -EAx PE = kqı92/r V = kQ/r F = kqıq2/r? E = kQ/r? F = qE C = q/AV APEE = -WE = -qEd APE = qAV PE = ½ QAV C = E0A/d ReqΣ R 1/ Req Σ 1/R P = IAV AV = IR R = pL/A F = ILB sino F = qvB sino EMF = NA DB/At B = Hol/2nr B = Honl Os = BA cosO IV1 = 12 V2 V1/V2 = N1/N2 EMF = NBAW sin(wt) Frequencey. W = 2nf = f = 1/T F = -kAx V = fA n = c/v An = Aair/n m PE = ½ kAx? V = fs ni sino1 = n2 sinO2 relachiorine o 1/o + 1/i = 1/f fo = fo = fs(1 ± °o/p) d sino = mA B = 10 log10 (1/lo) 2/l1 = r?/r,? d sino = (m + ½ )A m = -i/o f = R/2 P = 1/f E = hf Am T = 2.90 x 10 mK KEmax = hf – W Rn = (0.0529 nm) n² A = h/mv = h/p A-N = (h/mc)(1 – cosO) En = -13.6eV/n? L = nh/2n AxAp, 2 h/47 ΔΕΔt h/4π Fomg sing
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