y B (B=26.5) 56.0° A (A = 44.0) 28.0° C(C= 31.0) x 15. (II) For the vectors shown in Fig. 3-41, determine (a) B-2A. (b) 2A - 3B + 2C.

518۹ من ٥۱۹۰ Example 2; find O between A¯and B? A*=2î +3ƒ +k , B =3î -2j +k Example 3; if 0=30o between A¯and B'find q value? A¯=2î +2j +4k , B'=qî +j -2k Example 4; Find the angle between the vectors A¯=2î +3ƒ +1k , B` =-4î +2ƒ -1k منو يعرف يحل ذني الاسئله مالت الفيزياء de between4md 8 agnitude 2 and vect he angle a between 90, or 180. following situations must be. On each sit an one correct answ C , (c) A 8-6 B=30 betweenA"an d the angle between t N--4i +2 -1 دعاء صاحب حسین 4:19p äclul 21.02.04 II

P.6-20 Given that E(x, z; t) = a,0.1 sin (10x) in air, find H(x, z; t) and B. COS (6710ºt-Bz) (V/m)

39 SSM A tourist purchases a car in England and ships it home to the United States. The car sticker advertised that the car's fuel consumption was at the rate of 40 miles per gallon on the open road. The tourist does not realize that the U.K. gallon differs from the U.S. gallon: 1 U.K. gallon = 4.546 090 o liters 1 U.S. gallon = 3.785 411 8 liters. For a trip of 750 miles (in the United States), how many gallons of fuel does (a) the mistaken tourist believe she needs and (b) the car actually require?

What is the magnitude of Å + B + Č, where A = 1.00 i + 4.00 j - 1.00 k, B = 3.00 i - 1.00 j - 4,00 k and Č = -1.00 i + 1.00 j? A) 2.00 B) 6.78 C) 7.07 D) 8.12 E) 10.76

16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the following: I. value of summation and direction of VxII. value of summation and direction of Vy andIII. The value of resultant vector of velocity and the angle formed A. 262.66 m/s West ; 156.03 m/s North ; 305.51 m/s, 30.71 N of WB. 245.45 m/s North ; 145.02 m/s West ; 385.09 m/s, 39.09 W of NC. 156.23 m/s West ; 58.74 m/s North ; 166.91 m/s, 28.54 N of WD. 178.34 m/s North ; 65.36 m/s West ; 189.94 m/s, 19.34 W of N   21-25 A body is projected with an initial velocity of 25.5 m/s at 30 below the horizontal. Find: I. time of flight II. the maximum height attained by the body III. range A. Time of flight = 1.3s ; Maximum height = 7.7m ; Range = 55mB. Time of flight = 2.5s ; Maximum height = 8.7m ; Range = 60mC. Time of flight = 1.1s ; Maximum height = 6.9m ; Range = 45mD. Time of flight = 2.3s ; Maximum height = 9.7m ; Range = 65m

2-133. Determine the angle 0 between the pipe segments BA and BC. 3 ft 4 ft 2 ft 4 ft F = {30i – 45j + 50k} lb 4 ft

2- if A = 3i – j- 4k, B = -2i + 4j – 3k, Č = i + 2j – k, D = ai – 3j – 3k find : (d) B - Č (e) À - Bx ở (1) Ả × (B × C) (в) (А х В) х с (h) angle between Å · Č (i) value of 2 that makes the vectors D· C orthogonal. (j) The area of a parallelogram that B · C are Two adjacent sides on it. (k) value of 1 that makes the vectors D · Á orthogonal. (h) the component of Á in direction of B.

2–39. The force F acts on the bracket within the octant shown. If F = 400N, B = 60°, and y = 45°, determine the x, y, z components of F.

What is the sum of the following four vectors in (a) unit-vector notation, and as (b) a magnitude and (c) an angle? Positive angles are counterclockwise from the positive direction of the x axis; negative angles are clockwise. A→=(2.00⁢m)î+(3.00⁢m)ĵB→ = 4.00 m, at 65.0°C→=(-4.00⁢m)î-(6.00⁢m)ĵD→ = 5.00 m, at -235°