Write the given third order linear equation as an equivalent system of first order equations with initial values. S (1 − t²) y' − (4y" + 3 cos(t)y") = −3 sin(t) \y(3) = −3,_y′(3) = −2,_y'(3) = −2 Use Y1 = Y, y2 = y', and y3 = y". Y' = with initial values Y + Y -18 If you don't get this in 3 tries, you can get a hint.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 12CR
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Write the given third order linear equation as an equivalent system of first order equations with initial values.
ƒ (1 − t²) y' — (4y"" + 3 cos(t)y") = −3 sin(t)
-
\y(3) = −3, _y'(3) = −2, y″(3) = -2
Use
Y'
Y1 = Y,
with initial values
Y
Y2 = y', and
(0)
Y3 =y".
Y+
16
If you don't get this in 3 tries, you can get a hint.
Transcribed Image Text:Write the given third order linear equation as an equivalent system of first order equations with initial values. ƒ (1 − t²) y' — (4y"" + 3 cos(t)y") = −3 sin(t) - \y(3) = −3, _y'(3) = −2, y″(3) = -2 Use Y' Y1 = Y, with initial values Y Y2 = y', and (0) Y3 =y". Y+ 16 If you don't get this in 3 tries, you can get a hint.
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