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What is the momentum of a 1900 kg car that is sitting in the driveway?
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- You have been provided with specifications for case materials in the table below. However, you may also use your own figures for the mass of phones and test case materials. As you use this data, ensure that you have made the necessary SI unit conversions: Test Material Mass Collision TimePhone only (no case) 6.2 oz. 0.01 secondsSilicone 1.7 oz. 0.05 secondsHard Plastic 1.1 oz. 0.03 secondsRubber 3.2 oz. 0.08 seconds As the researcher, you will choose a drop height of between 1 and 2 meters. Using the provided mass of 6.2 oz, or by measuring the mass of a personal cell phone, determine the mass you will be using for your calculations. Remember to add the mass of the case material. 1) Using Newton’s second law, calculate the force of impact for each scenario.You have been provided with specifications for case materials in the table below. However, you may also use your own figures for the mass of phones and test case materials. As you use this data, ensure that you have made the necessary SI unit conversions: Test Material Mass Collision TimePhone only (no case) 6.2 oz. 0.01 secondsSilicone 1.7 oz. 0.05 secondsHard Plastic 1.1 oz. 0.03 secondsRubber 3.2 oz. 0.08 seconds As the researcher, you will choose a drop height of between 1 and 2 meters.Using the provided mass of 6.2 oz, or by measuring the mass of a personal cell phone, determine the mass you will be using for your calculations. Remember to add the mass of the case material. Use the information provided in your case specification document to calculate the velocity before impact and deceleration at impact. Remember that deceleration…You have been provided with specifications for case materials in the table below. However, you may also use your own figures for the mass of phones and test case materials. As you use this data, ensure that you have made the necessary SI unit conversions: Test Material Mass Collision TimePhone only (no case) 6.2 oz. 0.01 secondsSilicone 1.7 oz. 0.05 secondsHard Plastic 1.1 oz. 0.03 secondsRubber 3.2 oz. 0.08 seconds As the researcher, you will choose a drop height of between 1 and 2 meters. Using the provided mass of 6.2 oz, or by measuring the mass of a personal cell phone, determine the mass you will be using for your calculations. Remember to add the mass of the case material. 1) Following the creation of the force diagram, use the information provided in your case specification document to calculate…
- Which is the formula that describes the magnitude of impulse on an object? A. impulse = mass x acceleration B. impulse = mass x change in velocity C. impulse = mass * (velocity)2 x 0.5 D. impulse = mass x velocityThree objects A, B, and C are moving as shown in the figure below (Figure 1). Assume that A = 11.0 m/s, vB = 9.2 m/s, and vc = 4.0 m/s. Figure 5.0 kg B60° Vc. HA 6.0 kg 10.0 kg 1 of 1 > Find the x-component of the net momentum of the particles if we define the system to consist of A and C. Express your answer in kilogram meters per second. [ΠΙ ΑΣΦ ? Px = kg. m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Find the y-component of the net momentum of the particles if we define the system to consist of A and C. Express your answer in kilogram meters per second. OF [Π ΑΣΦ kg. m/s Request Answer Part C Find the x-component of the net momentum of the particles if we define the system to consist of B and C. Express your answer in kilogram meters per second. IVE ΑΣΦ ? kg. m/s Py = Submit Px =A South American tribe uses a unit of mass called the zooma. 1 zooma = 9 dooka. 1 boopa = 14 uma, 1 uma 16 dooka and 7 kg = 1 boopa. What is the mass of 120 zooma in kg? 426.7 kg O 17.9 kg 33.8 kg O8640 kg O 0.7 kg
- I don'n understand why the units are so off and how you get to seconds if you have kg*m/JAccording to Timothy Treadwell in 2001 "Now, the bears I live with average, the males are on average twelve hundred pounds. They're the largest bears in the world and they've been clocked at 41 [mph] and they've run a hundred meter dash in 5.85 seconds which human on stimulants doesn't even approach. a. Compute the speed of a grizzly bear using Mr. Treadwell's hundred-meter statement. b. Compute the momentum of a grizzly bear using the speed you calculated in part a. and the average mass stated by Mr. Treadwell. c. How fast would a 250 lb man have to run to have the same momentum you calculated in part b? d. How fast would a 4000 lb car have to drive to have the same momentum you calculated in part b?Kinetic energy KE (Chapter 5) has dimensions kgm2/s2. It can be written in terms of the momentum p (Chapter 6) and mass m as KE = p2/2m (a) Determine the proper units for momentum (p) using dimensional analysis. (b) Refer to Problem 2. Given the units of force, write a simple equation relating a constant force F exerted on an object, an interval of time t during which the force is applied, and the resulting momentum of the object, p.
- Physical quantities are classified as either vectors or scalars. Classify the following terms as either vectors or scalars: Force ii. Mass iii. Temperature iv. Velocity v. Momentum vi. TimeIn this problem we will observe how the momentum of an electron changes as its velocity approaches the speed of light. The mass of an electron is 9.109 × 10-31 kg Part (a) First, what is the momentum of an electron which is moving at the speed of a car on a highway, say 31 m/s, in kilogram meters per second? Part (b) What is the momentum of an electron moving at 18 % of the speed of light, in kilogram meters per second? Part (c) What is the momentum of an electron moving at 81 % of the speed of light, in kilogram meters per second? Part (d) What is the non-relativistic momentum of an electron moving at this speed (81 % of the speed of light), in kilogram meters per second? Part (e) When the electron is moving at 81 % of the speed of light, how many times greater is the relativistic momentum than the non-relativisticWhich of the following formulas describes the change in momentum of an object? A. change in momentum = force x distance over which force is applied B. change in momentum = force x time over which force is applied C. change in momentum = acceleration x distance over which acceleration is applied D. change in momentum = acceleration * time over which acceleration is applied