Wave Formula: Example: If a ray of red light has a wavelength of 660nm with a velocity of 3x108 . What is its frequency in air? Solution: f = v/λ f = 3x^10^8 / 660 x 10^-9 f = 4.55 x 10^14 Hz Kindly compute the following case exercises: a. A ray of yellow light has a wavelength of 560nm with a velocity of 3x108. What is itsfrequency in air? b. A ray of light has a frequency of 5.10 x 1014Hz. What is its wavelength in polycarbonate, where the ray travels at 1.89 x 108 meters? (round off your answer to 3 digits)

Wave Formula: Example: If a ray of red light has a wavelength of 660nm with a velocity of 3x108 . What is its frequency in air? Solution: f = v/λ f = 3x^10^8 / 660 x 10^-9 f = 4.55 x 10^14 Hz Kindly compute the following case exercises: a. A ray of yellow light has a wavelength of 560nm with a velocity of 3x108. What is itsfrequency in air? b. A ray of light has a frequency of 5.10 x 1014Hz. What is its wavelength in polycarbonate, where the ray travels at 1.89 x 108 meters? (round off your answer to 3 digits)

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter39: Relativity

Section: Chapter Questions

Problem 37PQ

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Concept explainers

Electromagnetic Waves

Electromagnetic waves are waves that consist of magnetic field and electric field components perpendicular to each other. These field components are also perpendicular to the direction of propagation of the wave.

Question

Wave Formula:

Example:
If a ray of red light has a wavelength of 660nm with a velocity of 3x108

. What is its frequency in air?

Solution:
f = v/λ
f = 3x^10^8 / 660 x 10^-9
f = 4.55 x 10^14 Hz

Kindly compute the following case exercises:

a. A ray of yellow light has a wavelength of 560nm with a velocity of 3x108. What is itsfrequency in air?

b. A ray of light has a frequency of 5.10 x 1014Hz. What is its wavelength in polycarbonate,
where the ray travels at 1.89 x 108 meters? (round off your answer to 3 digits)

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