Two smooth balls have a collision as shown in the figure. Ball A has a mass of Ma, and an initial velocity of va_initial at an angle of 0A_initial (counter-clockwise relative to the positive x-axis). Ball B has a mass of mg and is initially at rest. The coefficient of restitution for the collision is e.
Two smooth balls have a collision as shown in the figure. Ball A has a mass of Ma, and an initial velocity of va_initial at an angle of 0A_initial (counter-clockwise relative to the positive x-axis). Ball B has a mass of mg and is initially at rest. The coefficient of restitution for the collision is e.
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mA = 1.20 [kg]
mB = 0.55 [kg]
VA_initial = 1.75 [m/s]
Theta = 25 [degrees]
e = 0.44 [unitless]
b).Calculate the angle [degrees] that ball A leaves the collision. Provide this as a positive whole number (no decimal) counter clockwise from the positive x-axis. For most values of this problem the angle will be between 180-270 degrees.
Answer should be 220
Transcribed Image Text:Two smooth balls have a collision as shown in the figure. Ball A has a mass of
ma, and an initial velocity of vA_initial at an angle of 0a_initial (counter-clockwise
relative to the positive x-axis). Ball B has a mass of m; and is initially at rest.
The coefficient of restitution for the collision is e.
Calculate:
Determine the direction that Ball A leaves the collision, ĐA_final. Report the
angle as a positive number counter-clockwise from the positive x-axis.
y
A
VA_initial
Đz_initial
B
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