Two positive point charges +Q are fixed in place a distance b from a negative point charge qo, as shown. A student writes the following expression for the magnitude of the net electric force on qo: |EF| = 2kQqo b² b -90-$300 30° 30° b +Q +Q Is this expression correct? If it is, explain why it is a valid expression. If it is not, explain any errors and how to correct them, then write a correct expression for the net force.

College Physics
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Chapter1: Introduction: The Nature Of Science And Physics
Section: Chapter Questions
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please answer all parts of question

there is an equation sheet provided

part a) is an image and part b) is down below

b)  Say that you replaced the +? charge on the top with a negative charge of equal
magnitude (−?). How would the net force on ?# now compare to the net force from before? You
can answer without explicitly calculating this new force, but make sure you discuss both the
direction and magnitude of the force. Explain your reasoning. 

Two positive point charges +Q are fixed in place a distance b from a
negative point charge qo, as shown.
A student writes the following expression
for the magnitude of the net electric force on qo:
|EF|
=
2kQqo
b²
b
-90-$300
30°
30°
b
+Q
+Q
Is this expression correct? If it is, explain why it is a valid expression. If it is not, explain any errors
and how to correct them, then write a correct expression for the net force.
Transcribed Image Text:Two positive point charges +Q are fixed in place a distance b from a negative point charge qo, as shown. A student writes the following expression for the magnitude of the net electric force on qo: |EF| = 2kQqo b² b -90-$300 30° 30° b +Q +Q Is this expression correct? If it is, explain why it is a valid expression. If it is not, explain any errors and how to correct them, then write a correct expression for the net force.
|Epc|=
W = F - Ax = |F||Ax| cos
Mathematical Relations:
√2
sin (0)
kQ
p²
45°
1
45°
0
H
kQq
|²| = =
p2
1
| Ēroa| = 22
2kQ
Erod
rL
ΔΡΕ =
Vpc
=
cos(0)
=qAV
F = qË
EWext
kQ
A
H
H² = A² + 0²
30⁰
==▬▬▬▬
2kλ
√3/2
r
|Ē| :
= AE = AKE + APE + ··
tan (0)
=
=
Vsheet = Ex
60°
p = Qd
0
A
|Esheet | =
=
AV
Ax
Special Triangles:
Note that you can use these to determine the sine/cosine of the angles, e.g. cos(45) = 1/√2 = √2/2
1/2
2лkQ
A
= 2лko
0
5
37⁰
Wint = -APE
H
4
A
53°
3
Transcribed Image Text:|Epc|= W = F - Ax = |F||Ax| cos Mathematical Relations: √2 sin (0) kQ p² 45° 1 45° 0 H kQq |²| = = p2 1 | Ēroa| = 22 2kQ Erod rL ΔΡΕ = Vpc = cos(0) =qAV F = qË EWext kQ A H H² = A² + 0² 30⁰ ==▬▬▬▬ 2kλ √3/2 r |Ē| : = AE = AKE + APE + ·· tan (0) = = Vsheet = Ex 60° p = Qd 0 A |Esheet | = = AV Ax Special Triangles: Note that you can use these to determine the sine/cosine of the angles, e.g. cos(45) = 1/√2 = √2/2 1/2 2лkQ A = 2лko 0 5 37⁰ Wint = -APE H 4 A 53° 3
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