Two iron spheres with the same radius look identical from the outside, but one has a hollow cavity on the inside (see below). They are both heated to a temperature of 350° C and suspended by a thin cord from the ceiling of a vacuum chamber. The only way they can lose heat is by radiation. (a) Which sphere, if either, will radiate more watts of power? Explain your answer (b) Which sphere, if either, will cool down the fastest? Explain your answer.

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter11: Energy In Thermal Processes
Section: Chapter Questions
Problem 13P: A certain steel railroad rails 13 yd in length and weighs 70.0 lb/yd How much thermal energy is...
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Two iron spheres with the same radius look identical from the outside, but one has a
hollow cavity on the inside (see below). They are both heated to a temperature of 350°
C and suspended by a thin cord from the ceiling of a vacuum chamber. The only way
they can lose heat is by radiation. (a) Which sphere, if either, will radiate more watts
of power? Explain your answer (b) Which sphere, if either, will cool down the fastest?
Explain your answer.
a
b
interior view
Transcribed Image Text:Two iron spheres with the same radius look identical from the outside, but one has a hollow cavity on the inside (see below). They are both heated to a temperature of 350° C and suspended by a thin cord from the ceiling of a vacuum chamber. The only way they can lose heat is by radiation. (a) Which sphere, if either, will radiate more watts of power? Explain your answer (b) Which sphere, if either, will cool down the fastest? Explain your answer. a b interior view
Formulas:
Specific Heat:
(J/kg . °C)
Q = mc(T, – T,)
mAT
Mixtures:
Qoold =-Qhot
Latent Heat: phase change: Q=±mL
(T, – T.)
|
Thermal conductivity:
Q/t = Power =P=kA
Stefan's law of radiation:
P= σAeT4
Transcribed Image Text:Formulas: Specific Heat: (J/kg . °C) Q = mc(T, – T,) mAT Mixtures: Qoold =-Qhot Latent Heat: phase change: Q=±mL (T, – T.) | Thermal conductivity: Q/t = Power =P=kA Stefan's law of radiation: P= σAeT4
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