Two charges are located on the x axis: q₁ = +5.0 μC at x₁ = +4.2 cm, and q2 = +5.0 μC at x2 = -4.2 cm. Two other charges are located on they axis: 93 = +2.3 µC at y3 = +4.1 cm, and 94 = -5.5 µC at y4 = +6.2 cm. Find (a) the magnitude and (b) the direction of the net electric field at the origin. +V I 43 <--+x

Two charges are located on the x axis: q₁ = +5.0 μC at x₁ = +4.2 cm, and q2 = +5.0 μC at x2 = -4.2 cm. Two other charges are located on they axis: 93 = +2.3 µC at y3 = +4.1 cm, and 94 = -5.5 µC at y4 = +6.2 cm. Find (a) the magnitude and (b) the direction of the net electric field at the origin. +V I 43 <--+x

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.46P: A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Two charges are located on the x axis: q1 = +5.0 μC at x₁ = +4.2 cm, and q2 = +5.0 μC at x2 = -4.2 cm. Two other charges are located on
the y axis: 93 = +2.3 µC at y3 = +4.1 cm, and 94 = -5.5 µC at y4 = +6.2 cm. Find (a) the magnitude and (b) the direction of the net electric
field at the origin.
(a) Number i
(b) The net electric field points
Units
42
<
41
--+x

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Step 3: Calculation for electric field at origin due to charge q1.

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Step 4: Calculation for electric field at origin due to charge q2.

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Step 5: Calculation for electric field at origin due to charge q3.

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Step 6: Calculation for electric field at origin due to charge q4.

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Step 7: Calculation for magnitude of net electric field.

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Step 8: Calculation for direction of net electric field.

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