Titration of isoleucine by a strong base, for example NaOH, reveals two pk's. The titration reaction occurring at pK₂ (pK₂ = 9.68) is:= COOH+ NH2O a -C0O-+-NH,O b. -NH₂ + OH- =NH+H2O.O G.COOH + NHO d. -NH₂ + OH-O e. -COOH + OH" =00+-NH₂.NH, THỌ.-COO + H₂O.

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Titration of isoleucine by a strong base, for example NaOH, reveals two pk's. The titration reaction occurring at pK₂ (pK₂ = 9.68) is: ( a -C00O" + NH = –COOH+ NH2 O b. -NH₂ + OH = NH+H2O. OC. O d. -COOH +-NH. -NH₂ + OH- -COOH + OH" = 00+-NH₂. NH, THỌ, -COO + H₂O.

Titration of isoleucine by a strong base, for example NaOH, reveals two pk's. The titration reaction occurring at pK₂ (pK₂ = 9.68) is: ( a -C00O" + NH = –COOH+ NH2 O b. -NH₂ + OH = NH+H2O. OC. O d. -COOH +-NH. -NH₂ + OH- -COOH + OH" = 00+-NH₂. NH, THỌ, -COO + H₂O.

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter20: Carboxylic Acids And Nitriles

Section20.3: Biological Acids And The Henderson–hasselbalch Equation

Problem 5P: Calculate the percentages of dissociated and undissociated forms present in the following solutions:...

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Question

Titration of isoleucine by a strong base, for example NaOH, reveals two pk's. The titration reaction occurring at pK₂ (pK₂ = 9.68) is:
= COOH+ NH2
O a -C0O-+-NH,
O b. -NH₂ + OH- =
NH+H2O.
O G.COOH + NH
O d. -NH₂ + OH-
O e. -COOH + OH" =
00+-NH₂.
NH, THỌ.
-COO + H₂O.

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