Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be : Y m = 150 g 3. 50 g = m, m2= 100 g 60°

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be : Y m = 150 g 3. 50 g = m, m2= 100 g 60°

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 62P

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Question

Correct solution needed

Three particles of masses 50 g, 100 g and 150 g are placed
at the vertices of an equilateral triangle of side 1 m (as
shown in the figure). The (x, y) coordinates of the centre of
mass will be :
m3 = 150 g
%3D
50 g = m,
m, = 100 g
60°
0.5 m
1.0 m

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