The speed of a particle moving along a circle of radius r=4 m, is v(t) = 4t, where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s) of the particle at t = 1s is The speed of a particle moving along a circle of radiusr = 4 m, is v(t) = 4t; where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s) of the particle at t= 1s is:O a. 4.0O b.5.4OG. 8.9O d. 2.1O e. 6.7

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Description: The speed of a particle moving along a circle of radius r=4 m, is v(t) = 4t, where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s) of the particle at t = 1s is The speed of a particle moving along a circle of radiusr = 4 m

Given: Radius of the circle, r = 4 m. Time, t =1 s. v(t) = 4t. To Find: The total acceleration.

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The speed of a particle moving along a circle of radiusr=4 m, is v(t) = 4t; where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s-) of the particle at t= 1s is: %3D O a. 4.0 Ob.5.4 OG 8.9 Od.2.1

The speed of a particle moving along a circle of radiusr=4 m, is v(t) = 4t; where v is in m/s and t is in s. The magnitude of the total acceleration (in m/s-) of the particle at t= 1s is: %3D O a. 4.0 Ob.5.4 OG 8.9 Od.2.1

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 80AP: A particle travels m a circular orbit of radius 10 m. Its speed is changing at a rate of 15.0m/s2 at...

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