The solution of the equation of motion of a simple pendulum is given by: 8(t) = 0.2 cos(5nt), where 8 is in radians and t in seconds. Determine the angular speed of the bob, when it passes through its lowest point. Oe' = ±0.1 rad/s e' = ±n rad/s e' = ±0.2π rad/s e' = n/2 rad/s

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 29P: The angular position of a pendulum is represented by the equation = 0.032 0 cos t, where is in...
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= 200 N/m and E = 4 J
The solution of the equation of motion of a simple pendulum is given by: 8(t) = 0.2
cos(5nt), where 8 is in radians and t in seconds. Determine the angular speed of
the bob, when it passes through its lowest point.
Oe' = ±0.1 rad/s
e' = ± rad/s
e' = ±0.2π rad/s
e' = n/2 rad/s
Istring with length L1. When set into a
Transcribed Image Text:= 200 N/m and E = 4 J The solution of the equation of motion of a simple pendulum is given by: 8(t) = 0.2 cos(5nt), where 8 is in radians and t in seconds. Determine the angular speed of the bob, when it passes through its lowest point. Oe' = ±0.1 rad/s e' = ± rad/s e' = ±0.2π rad/s e' = n/2 rad/s Istring with length L1. When set into a
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