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- Three cables are used to hold a hot-air balloon in place. The tension in the cable AD is 658 N. Draw the Free Body Diagram at A. Upload this along with your all your workings for this problem to the dropbox. What is the tension in the cable AB? Enter using 3 significant figures. What is the tension in the cable AC? Enter using 3 significant figures. What is the vertical force V exerted by the balloon at point A? Enter using 4 significant figures.can you pls answer a-e. a is not in the pic but reads: if mass is 85kg. and the applied force is 95N at 27degrees above the horizontal. what is the coefficient of kinetic friction? here’s b-e. thank u!!!!Please referto the figure at the right side for the following questions: 1. a. Determine the magnitude of the resultant force and its direction, В 30 N 10 kg measured counterclockwise from D positive x- axis of forces OC and OH only. b. Resolve force OB into its x,y and z 60° 159 3m E 70 N 60 50 N / components, express its force as a cartesian vector and determine the 4m 300 75 N coordinate direction angles of the 60 N Y K force OB. A 4 m c. Determine the angle between OB and Ol. 70° 45° F 65 N d. Determine the magnitude of the 3 m resultant forces and its direction acting in the figure. Sketch your 50 N 80° 80 N result. 90 N 40 N
- A 150 lb box sits on a smooth horizontal surface, while a second downward force of 35 lbs is also applied to th box. On the diagram below, sketch the force vectors acting on the box and determine the magnitude and direction of the Normal force.wo blocks of masses m and 2m are held in equilibrium on a frictionless incline as in the figure. In terms of m and θ, find the following. (Use any variable or symbol stated above along with the following as necessary: g.) An inclined plane makes an angle θ with the horizontal. One end of a cord labeled T2 is attached to place near the top of the inclined plane, and the other end of the cord is attached to the uphill side of a block of mass m1 that is resting on the incline. A second cord, labeled T2, is attached to the downhill side of the block of mass m, and the other end is attached to the uphill side of a block of mass 2m, which is near the bottom of the incline. (a) the magnitude of the tension T1 in the upper cordT1 = (b) the magnitude of the tension T2 in the lower cord connecting the two blocksT2 =Problem A sold uniform ball with mass mand dlameter dis supported against a vertical frictioniess wall by a thin massiess wire of length L. a) Find the tension in the wire. m Solution a) Let us first derive the expression for the tension. By Newton's First LN IF the componenes of force that makes this so is Simplifying this results to T- Analyaing the figure above, we arrive at 2. By substitution, we arrive at the following T- sarti if the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T- 0.370 N
- A warehouse worker pushes a crate along the floor, as shown in the figure (Figure 1), by a force of 19 NN that points downward at an angle of 45 degrees below the horizontal. Find the horizontal component of the push. Your answer should be positive if the force is to the right, negative if the force is to the left. Express your answer in newtons. Find the vertical component of the push. Your answer should be positive if the force is upward, negative if the force is downward. Express your answer in newtons.Name ver ve Problem 2 Section A 50.0-kg block is being pushed down a 16.0° slope by a force Ê of magnitude 250 ove directed at an angle of 25.0° from the horizontal as shown on the figure. The block moves down the incline plane. The coefficient of kinetic friction between the block and the Blope to 0.200. a) brock. babel each force clearly. Also show your x- and y-axes clearly. | Draw the free body diagram of the block showing all the forces acting on the |25.00 ) 16.0° b) [6 mri Calculate the magnitude of the normal force. hand the the top of Calculate the magnitude of the acceleration of the block. 20.0 peed B0 flling with pointa]You come across a picture of three copalanar forces, acting at a point p. The first is 200N and acting at 20degree to the horizontal; the second is 400N and acting at 165degree to the horizontal; the third 500N acting at 250 degrees to the horizontal. Draw what you see in the picture using an appropriate scale use protractor for the angle. B) with the information above show that the magnitude and the direction of the resultant of the three copalanar forces are respectively 474.6N and 38.88 degree
- Given a 500 x 750-mm rectangular plate, of mass m = 50 kg, and held in a vertical plane as shown. All connections consist of either frictionless pin, roller, or short link. Compute the horizontal component of the reaction (in Newtons) at D (use g = 9.81 m/s^2). Round-off your answer to 2 decimal places only. * D 'B АA skier is standing on a 30o hill. Draw the hill and add idealized force vectors that represent the force of the skier (FS), the normal force (FN), and the force of friction (FF).Consider (Figure 1) Assume F = 380 N Figure 3 m 4m Part A Determine the moment of force F about point O Express the result as a Cartesian vector Enter the x, y and components of the moment of force separated by commas. Express your answers in kilonewton-meters to three significant figures. View Available Hint(s) ✓ Hint 1. Cartesian Vector Formulation for the Moment of a Force ijk Ty T. where Tz. F F F Ty, T, represent the zy, z components of the position vector drawn from O to any point on the line of action of the force, F., Fy, F represent the z. y. z components of the force vector in this problem, r, and F. components are equal to zero, since the line of action of the force lies in the z-y plane For simplicity, consider using vector r that lies on either of the axes z or y, since in that case you need only one non-zero coordinate to express its position If zy, z coordinate axes are established, then the moment equation can be written in determinant form as Mo=rx F = T₂ Mo = Submit…