The input to a full-wave rectifier is 10 V AC (RMS). The load resistor is 10 ohms and rectifier losses are 4W. The power efficiency of the rectifier is: O A. 58 % O B. None of the other choices are correct O C. 100 % O D. 80 % O E. 67%
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- What is the difference between a diode and rectifier?A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%The input to a full-wave rectifier is 30 V AC (RMS). The load resistor is 10 ohms. The DC power at the output is: O A. 73 W O B. 18 W C. None of the other choices are correct D. 36 W O E. 146 W
- A full-wave rectifier uses 2 diodes. The internal resistance of each diode is 20 02. The transformer RMS secondary voltage from centre tap to each end of the secondary is 50 V and the load resistance is 980 2. Mean load current will beZener Diode conducts current in a. reverse direction O b. both reverse and forward O c forward direction Od. Depend of the voltageThe power output of the half-wave rectifier is rated at 102.4 W with a load resistor of 40 ohms. The RMS voltage at the output is: O A. None of the other choices are correct O B. 12.5 V O C. 102 V O D. 25.5 V O E. 51 V
- In a half wave rectifier, the sine wave input is 55sin55t. If the load resistance is of 1K, then DC power output will be? a. 0.3W b. 3.99W c. 5.97W d. 6.77WIn a half wave rectifier, the input sine wave is 200sin200 nt Volts. If load resistance is of 1k then the average DC power output of half wave rectifier is O 4.016 W O 5.016W O 3.25W O 6.25W O not all aboveC4 R1 Vout For the precision rectifier circuit shown in Figure C4 what is the correct operation for the circuit if a Sine wave is 10k D1 R2 LM324 VEE applied to the input signal VIN? Vin D2 10k OUT V3 U1A Figure C4 A. When VIn is negative the circuit operates as unity voltage follower providing an in phase sine wave at VouT. When VIN is positive the circuit conducts but only to one diode drop, B. When VIn is negative the circuit operates as an inverting amplifier providing an inverted sine wave at VouT. When VIN is positive the circuit is driven to very close to zero due to amplifier gain reducing the diode drop voltage, c. When VIn is negative the circuit operates as an inverting amplifier providing an in-phase sine wave at VOUT. When VIn is positive the circuit is driven to very close to zero due to amplifier gain reducing the diode drop voltage, D. When VIn is negative the circuit operates as unity voltage follower providing an inverted sine wave at Vour. When VIn is positive the…
- The input to a full-wave rectifier is 40 V AC (RMS). The load resistor is 10 ohms. The DC voltage at the output is: O A. 27 V O B. 18 V O C. 36 V O D. None of the other choices are correct O E. 21 VThe power output of the half-wave rectifier is rated at 51.2 W with a load resistor of 20 ohms. The peak voltage at the output is: O A. 25 V O B. 203 V O C. None of the other choices are correct O D.51 V O E. 102.5 VA 1 - ∅ full-wave rectifier is made by using thyristors. If the peak value of the sinusoidal input voltage is Vm and the value of the delay angle is 45 degree, find the average value of output voltage Select one: a. 0.65 VM b. 0.85 VM c. 0.45 VM d. 0.25 Vm