The electric field strength between a pair of plates 4.0cm in length in a cathode ray tube has a value of 23000N/C. An electron enters the field at right angles at a velocity of 3.7x10^7 m/s from left to right. What is the velocity and direction of the electron as it leaves the field?

The electric field strength between a pair of plates 4.0cm in length in a cathode ray tube has a value of 23000N/C. An electron enters the field at right angles at a velocity of 3.7x10^7 m/s from left to right. What is the velocity and direction of the electron as it leaves the field?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 31PQ

See similar textbooks

Related questions

Q: An electron with a horizontal speed of 2300000 m/s and no vertical component of velocity passes…

Q: If the intensity of electric field at a distance x from the centre in the axial position of a small…

Q: An electron travelling at 3.00 x 10° m/s moves into a uniform electric field and is brought to rest…

Q: 2. An inifite charged sheet with surface charge density o = 4µC/m². The magnetude of electric field…

Q: nside a radiation therapy device, an electron is in the presence of a uniform electric field with a…

A: Electric Force Fe=qE ....1 where q is charge E is electric field GIVEN : E = 325 N/C For electron…

Q: A thin copper plate of diameter 6.00 cm is charged to 8.40 nC. What is the strength of the electric…

Q: What is the magnitude of the electric field 10 cm from the center of a 14 cm radius solid sphere…

Q: In the figure, q1=1.00×10−7 C and q2=7.00×10−7 C. What is the magnitude E of the electric field…

A: q1=1.00×10−7 C and q2=7.00×10−7 C.

Q: Two parallel metallic sheets of equal area 8cm? are separated by a distancel.5cm. One sheet carries…

A: Electrostatics is the study of static charges. Each charge in this world attracts/repels every other…

Q: How far the test charge of 0.0056c must reside inside Electric Field with intensity of 0.007N so…

A: When the test charges come inside the electric field then it experiences the force due to the charge…

Q: Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of…

Q: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction…

A: Given data: Electric field (E) = 700 N/C Mass of proton (mp) = 1.67×10-27 kg Charge on a proton (q)…

Q: (a) Find the electric field 10.0 cm from the filament, where distances are measured perpendicular to…

A: Given data: The charge per unit length of filament is: λ = -90.6μC/m The electric field is: E Let us…

Q: An electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is…

A: Given: An electron accelerates in an electric field, E = 1.45×104 N/C Mass of electron, m =…

Q: A proton is placed in an electric field of intensity 400 N/C. What are the magnitude and direction…

A: The intensity of the electric field is, The proton’s mass is, The change on a proton is,

Q: An electron with kinetic energy of 5.0 10-16 J is moving to the right along the axis of a…

Q: The velocity of a particle (m = 10 mg, q = - 4.0 µC) at t =0 is 20 m/s in the positive x-direction.…

A: From basic kinematic equations, we know that v= u+at Here u= 20 m/s t= 10.5 s Acceleration is due…

Q: At some instant the velocity components of an electron moving between two charged parallel plates…

Q: The velocity of a particle (m = 10 mg, q = - 4.0 uC) at t = 0 is 20 m/s in the positive x-direction.…

Q: What is the magnitude of the electric field produced by a helium (+2e) nucleus at distance of 1.41…

Q: An electron (q=1.6x10-19 C, m=9.11x10-31 kg) is released (from rest) in a uniform E-field with a…

A: The force on a particle in a electric field is given as Fe=qE Substituting the values in the above…

Q: What is the electric field intensity 2 m from the surface of the rod, 20cm in diameter, having a…

A: Given diameter d=20cm and area A = 4πR2 r = 2 m + 0.2 m = 2.2 m r is distance of point from…

Q: A proton moves at 4.50 x 105 m/s in the horizontal direction. It enters a uniform vertical electric…

A: The proton travel the horizontal distance, The horizontal velocity of the proton,

Q: The electric field is zero everywhere except in the region 0 where there is a uniform electric field…

Q: The electric field 20 mm to the right from a certain charge has a magnitude of 1.0 x 10^5 N/C and is…

A: Given The electric field at r = 20 mm is E=1×105 N/C. The distance at which electric field is…

Q: A point charge for which Q=5x10^-16C and m=2x10^-26 kg is moving in the combined fields…

A: Solution : Given: Q= 5×10-16Cm= 2×10-26kgE= 100 ax-300ay+ 200az V/mB= -ax+…

Q: What is the magnitude of the electric force on an electron in a uniform electric field of strength…

A: We have an electron placed in the presence of a uniform electric field of magnitude E=1610 N/c…

Q: a distance of 0.20 from the center of a conducting sphere with a charge and radius 0.10 cm. the…

Q: An electric field of intensity 3.40 kN/C is applied along the x-axis. Calculate the electric flux…

Q: an electron (m = 9.11x10-31 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is…

A: Given Charge is q=1.60×10^-19 C Mass of an electron is m=9.11×10^-31 kg Electric field is…

Q: An electron (m 9.11x101 kg) accelerates in a uniform electric field E = 1.45 x 10 N/C. What is the…

Q: Inside a radiation therapy device, an electron is in the presence of a uniform electric field with a…

A: Given data The magnitude of the electric field is given as E = 325 N/C. The time interval is given…

Q: Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of…

A: Given: The magnitude of the electric field is E=275 N/C,

Q: An electron (m = 9.11x1031 kg) accelerates in a uniform electric field E = 1.45 x 104 N/C. What is…

Q: A new kind of electron gun has a rear plate at −25.0 kV, a grounded plate 2.00 cm in front of that,…

A: The expression to find the average electric field is E=∆Vd=25.0 kV--25.0 kV6.00×10-2 m=8.33×105 Vm

Q: Two 4.00-cm wide charged plates oriented horizontally source a vertical, uniform 100-N/C electric…

A: Given:- Vox = 3×106 m/sVoy =0 m/sE = 100 N/C

Q: Scientists in the laboratory create a uniform electric field E = 9.0x105 k V/m in a region of space…

Q: the total charge on the plate and the electric field intensity at (0,0,10)

Q: What is the magnitude of the electric field 4.52 cm to the left of 8.15 mC negative charge?…

A: Answer:- (b) 3.59 × 1010 N/C Given Charge (q) = 8.15 mC = 8.15 × 10-3 C Distance (r) = 4.52 cm =…

Q: A doubly charged helium atom, whose mass is 6.6 x 10-27 kgis accelerated by a voltage of 3200 V.(a)…

A: mass, m = 6.6 x 10-27 kg charge, q = 3.2 x 10-19 C Voltage, V =3200 V Magnetic field, B = 0.24 T

Q: An electron with a horizontal speed of 2300000 m/s and no vertical component of velocity passes…

A: Derivation of angle of deviation formula: Along horizontal, ux=v0 x=L t=Lv0 vx=v0 Motion along…

Q: 0.5 m 0.5 m +2.00 -1.00 nC 1.00 m nC 1.00 m Pt. a 1.00 m Pt. c

A: Given, a positive charge whose magnitude is 2×10-9 C. a negative charge whose magnitude is 1×10-9 C.…

Q: At a certain point in a material, the flux density is 0.09 C/m2 and electric field intensity is 1.2…

A: Given data σ=0.09 C/m2E=1.2×109 V/m

Q: An electron with a horizontal speed of 4600000 m/s and no vertical component of velocity passes…

Q: An electron with a speed of 5.63 × 108 cm/s in the positive direction of an x axis enters an…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

100%

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

An electron is moving in the +x-direction with a speed of 5.0 x10^6 m/s.There is an electric field of 3.0kV/m in the +x-direction .What will be the election's speed after it has moved 1.00cm along the field.
An electron with speed v0 = 3388829.6m/s travels parallel to and along the same direction as an electric field of magnitude E = 3154N/C. (a) How far will the electron travel before it stops? Answer in SI units and multiply your answer by 10^2. (b) How much time will elapse before it returns to its starting point? Answer in SI units and multiply your answer by 10^8.
An electron has an initial velocity of 2.4x106 m/s in the +x direction. It enters a uniform electric field E = 397 N/C which is in the +y direction. What is the ratio of the y-component of the velocity of the electron to the x-component of the velocity after traveling 5 cm in the +x direction in the field? (Your result must include 2 digit after the decimal point and maximum of 5% of error is accepted in your answer. Take elementary charge 1.6x10-19 C and take mass of electron 9.1x10-31 kg.)
An electron flies into a constant electric field (along the direction of the lines of E-field). The initial electron velocity is 10 km/s. Calculate the magnitude the electric field if the electron stops in 6 nsec. The electron mass is me =9.11×10-31 kg, the electron charge is qe = -1.61×10-19 C. The electric field, E = Units .
An electron moving parallel to a uniform electric field increases its speed from 2.0××1077 m/sm/s to 4.0××1077 m/sm/s over a distance of 1.9 cmcm. What is the electric field strength?
You are working on a research project in which you must control the direction of travel of electrons using deflection plates. You have devised the apparatus shown. The plates are of length ℓ = 0.500 m and are separated by a distance d = 3.00 cm. Electrons are fired at υi = 5.00 x 106 m/s into a uniform electric field from the left edge of the lower, positive plate, aimed directly at the right edge of the upper, negative plate. Therefore, if there is no electric field between the plates, the electrons will follow the broken line in the figure. With an electric field existing between the plates, the electrons will follow a curved path, bending downward. You need to determine (a) the range of angles over which the electron can leave the apparatus and (b) the electric field required to give the maximum possible deviation angle.
Question 1 a) In J. J. Thomson experiment (1897), an electron moving horizontally with a constant speed vo enters in between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d, is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge to mass ratio, i.e. e/m to be 2v,Y/CEL). (Recall that Thomson received Nobel Prize for his achievement.) b) Calculate e/m, knowing the following data. E=1.6x10* Newton/Coulomb, L=10 cm, Y=2.9 cm, v=2.19x10* km/s. (Be careful to use coherent units.)
The velocity of a particle (m= 10 mg, q= -4 microC) at a t=0 is 20m/s in the positive x-direction. If the particle moves in a uniform electric field of 20 N/C in the positive x-direction, what is the particle's velocity (in m/s) at t = 11.9 s ?
A particle (mass = 4.0 g, charge = 52 mC) moves along the x-axis in a region of space where the electric field is uniform and is given by Ex = - 2.5 N/C If the velocity of the particle at t = 0 is given by vx = 80 m/s, what is the velocity of the particle at t = 2.0 s? Select one: O A. -56.50 m/s O B. 15.00 m/s O C. -180.00 m/s O D. -17.50 m/s
A particle (mass=4.0 g, charge=80 mC) moves in a region of space where the electric field is uniform and is given by Ex= -2.5 N/C, if the velocity of the particle at t=0 is given by vx= 120 m/s, what is the speed (in m/s) of the particle at t=2.0 s? Select one: O a. 20 O b. 40 O c. 30 O d. 60
At some instant the velocity components of an electron moving between two charged parallel plates are vx-1.6×105 m/s and vy-3.3x10³ m/s. Suppose the electric field between the plates is uniform and given by E = (120N/C).1 . In unit-vector notation, what are (a) the electron's acceleration in that field and (b) the electron's velocity when its x coordinate has changed by 2.2 cm? (a)(i - )j.
In the figure, q1=1.00×10−7 C and q2=7.00×10−7 C. What is the magnitude E of the electric field at the point ((x,y)=(0.00 cm,3.00 cm)? What is the angle θE that the direction of the electric field makes at that position, measuring counterclockwise from the positive x-axis? What is the magnitude F of the force acting on an electron at that position?