• The cable lifting an elevator (600-kg) is wrapped around a 1.0-m diameter cylinder (20-kg) that is turned by the elevator's motor. The elevator is moving upward at a speed of 2.0-m/s then slows to a stop. (Note: I(cylinder)= ½ M R²) What is the angular acceleration (a) of the cylinder? а. b. What is the net torque (t) on the cylinder to stop the elevator's motion? What are the initial and final angular velocities (@) of the rotor. с.

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Chapter7: Rotational Motion And The Law Of Gravity
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Group Work
• The cable lifting an elevator (600-kg) is wrapped around a 1.0-m diameter cylinder
(20-kg) that is turned by the elevator's motor. The elevator is moving upward at a
speed of 2.0-m/s then slows to a stop.
(Note: I(cylinder)= ½ M R²)
What is the angular acceleration (a) of the cylinder?
What is the net torque (T) on the cylinder to stop the elevator's motion?
а.
b.
What
the initial and final angular velocities (@) of the rotor.
с.
d.
What angle (A0) does the cylinder cover while stopping?
How long does it take to stop the elevator?
е.
Transcribed Image Text:Group Work • The cable lifting an elevator (600-kg) is wrapped around a 1.0-m diameter cylinder (20-kg) that is turned by the elevator's motor. The elevator is moving upward at a speed of 2.0-m/s then slows to a stop. (Note: I(cylinder)= ½ M R²) What is the angular acceleration (a) of the cylinder? What is the net torque (T) on the cylinder to stop the elevator's motion? а. b. What the initial and final angular velocities (@) of the rotor. с. d. What angle (A0) does the cylinder cover while stopping? How long does it take to stop the elevator? е.
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