Self-closing refrigerator door A door is constructed of a thin homogeneous slab of material of width w, with frictionless hinges. If the door is opened through an initial angle ao < π/2, and it is released at rest, it closes itself in a time t. Find a formula for the angle d that the line of hinges makes with the vertical, in terms of w, ao, t and g. Use your formula to find 8 (in degrees) for the case w=0.86m, ao = π/4, t = 1.5s, g = 9.81m/s². Is this consistent with your experience with your refrigerator? (Recall that the moment of inertia of a rod of mass m and length & about one of its ends is ml²/3.)

International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.50P: The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the...
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Question 3. Please attempt.
(1) Make a
3. Self-closing refrigerator door A door is constructed of a thin homogeneous slab of material of width w, with frictionless
hinges. If the door is opened through an initial angle ao </2, and it is released at rest, it closes itself in a time t.
Find a formula for the angle & that the line of hinges makes with the vertical, in terms of w, ao, t and g. Use your
formula to find 8 (in degrees) for the case w = 0.86m, ao = π/4, t = 1.5s, g = 9.81m/s². Is this consistent with your
experience with your refrigerator? (Recall that the moment of inertia of a rod of mass m and length & about one of
its ends is ml2/3.)
Some possibly useful formulas:
F = ma,
p = mv, F = P₁
L=rxp, N = 7x F = L
W₁+2 = ₁² ds. F(F),.
Fk=kFN, 0 ≤ Fs ≤s FN,
F21 = -Gm₁m₂2₁-23, F21 = Q1Q2 71-773
1/μ = 1/m₁ + 1/m2, M = m₁ + m2, R= (miri+m₂r2)/M,
P = MR, T = MR² +47²2, L=Rx MR+Fx μr,
V(r) = ar+1 ⇒T="¹
T = T2 - T1
Central Potential Problem: Vor(r) = ² +V(r).
69°F
Sunny
ESC
of your solution for use later in the semester.
1
S
2
O
10
3
F3
4
%
Q Search
01
T
A
LD
6
0 = 17-21.
.
7
C
G
8
FB
σ(Ω) =
1
H
9
FB
F(T) = -VV (F)
P
στ = IdΩσΩ)
* +1
20
-E
=
D
BACKSPACE
1
1
3:21 PM
11/13/2023
o
Transcribed Image Text:(1) Make a 3. Self-closing refrigerator door A door is constructed of a thin homogeneous slab of material of width w, with frictionless hinges. If the door is opened through an initial angle ao </2, and it is released at rest, it closes itself in a time t. Find a formula for the angle & that the line of hinges makes with the vertical, in terms of w, ao, t and g. Use your formula to find 8 (in degrees) for the case w = 0.86m, ao = π/4, t = 1.5s, g = 9.81m/s². Is this consistent with your experience with your refrigerator? (Recall that the moment of inertia of a rod of mass m and length & about one of its ends is ml2/3.) Some possibly useful formulas: F = ma, p = mv, F = P₁ L=rxp, N = 7x F = L W₁+2 = ₁² ds. F(F),. Fk=kFN, 0 ≤ Fs ≤s FN, F21 = -Gm₁m₂2₁-23, F21 = Q1Q2 71-773 1/μ = 1/m₁ + 1/m2, M = m₁ + m2, R= (miri+m₂r2)/M, P = MR, T = MR² +47²2, L=Rx MR+Fx μr, V(r) = ar+1 ⇒T="¹ T = T2 - T1 Central Potential Problem: Vor(r) = ² +V(r). 69°F Sunny ESC of your solution for use later in the semester. 1 S 2 O 10 3 F3 4 % Q Search 01 T A LD 6 0 = 17-21. . 7 C G 8 FB σ(Ω) = 1 H 9 FB F(T) = -VV (F) P στ = IdΩσΩ) * +1 20 -E = D BACKSPACE 1 1 3:21 PM 11/13/2023 o
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