Sample 1 43.07 g 42.05 g 1.02 g 8.95 mL .98 mL Sample 2 42.77 g 41.09 g 1.68 g 22.66 mL 8.95 mL 13.71 mL Mass of flask and KHP Mass of empty flask Mass of KHP Final buret reading Initial buret reading Volume of base used 7.97 mL Calculations: In the spaces below, show calculation set-ups for Sample 1 only. Show the answers for both samples in the boxes. Remember to use the correct number of significant figures in all calculations. (Ex. The number 0.005 has only 1 significant figure.) Calculations Table Sample 1 = 0.00499 moles KHP 1.68 g x 1 mole = 0.00822 moles KHP Sample 2 1. Moles of acid (KHP, molar mass = 204.2 1.02 g x 1 mole 204.2 g/mole 204.2 g/mole g/mole). Show calculations for Sample 1 here. 2. Moles of base used to neutralize the acid above. Show calculations for Sample 1 here. 3. Molarity of base (N2OH). Show calculations for Sample 1 here.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.12QAP
icon
Related questions
icon
Concept explainers
Question

Titration lab - need help with the following questions and how to set up the formulas, thank you!

Moles of base used to neutralize a base of 7.97 ml (sample 1) and 13.71 ml (sample 2)

Molartity of base (NaOH)

Average molarity of base 

Sample 1
43.07 g
42.05 g
1.02 g
Sample 2
42.77 g
41.09 g
1.68 g
Mass of flask and KHP
Mass of empty flask
|Mass of KHP
Final buret reading
Initial buret reading
Volume of base used
8.95 mL
22.66 mL
.98 mL
8.95 mL
7.97 mL
13.71 mL
Calculations: In the spaces below, show calculation set-ups for Sample 1 only. Show the
answers for both samples in the boxes. Remember to use the correct number of significant
figures in all calculations. (Ex. The number 0.005 has only 1 significant figure.)
Calculations Table
Sample 1
= 0.00499 moles KHP
Sample 2
1.68 g x 1 mole = 0.00822 moles KHP
204.2 g/mole
1. Moles of acid (KHP,
1.02 g x 1 mole
204.2 g/mole
molar mass = 204.2
%3D
g/mole). Show
calculations for Sample 1
here.
2. Moles of base used to
neutralize the acid above.
Show calculations for
Sample 1 here.
3. Molarity of base
(N2OH). Show
calculations for Sample 1
here.
Transcribed Image Text:Sample 1 43.07 g 42.05 g 1.02 g Sample 2 42.77 g 41.09 g 1.68 g Mass of flask and KHP Mass of empty flask |Mass of KHP Final buret reading Initial buret reading Volume of base used 8.95 mL 22.66 mL .98 mL 8.95 mL 7.97 mL 13.71 mL Calculations: In the spaces below, show calculation set-ups for Sample 1 only. Show the answers for both samples in the boxes. Remember to use the correct number of significant figures in all calculations. (Ex. The number 0.005 has only 1 significant figure.) Calculations Table Sample 1 = 0.00499 moles KHP Sample 2 1.68 g x 1 mole = 0.00822 moles KHP 204.2 g/mole 1. Moles of acid (KHP, 1.02 g x 1 mole 204.2 g/mole molar mass = 204.2 %3D g/mole). Show calculations for Sample 1 here. 2. Moles of base used to neutralize the acid above. Show calculations for Sample 1 here. 3. Molarity of base (N2OH). Show calculations for Sample 1 here.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Ionic Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage