R1 40 V R2 v. RL a. Design the divider circuit to meet the specifications just mentioned. Specify the numerical values of R, and R2. b. Assume the power ratings of commercially available resistors are 1/16, 1/8, 1/4, 1. and 2 W. What power rating would vou specifv?

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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The no-load voltage in the voltage-divider circuit shown in Fig. P3.140
is 8 V. The smallest load resistor that is ever connected to the divider is 3.6 kN. When
MULTISIM
PROBLEM
the divider is loaded, v, is not to drop below 7.5 V.
Figure P3.14
R1
40 V
R2
v. §RL
a. Design the divider circuit to meet the specifications just mentioned. Specify the
numerical values of Rị and Rg.
b. Assume the power ratings of commercially available resistors are 1/16, 1/8, 1/4,
1, and 2 W. What power rating would you specify?
Transcribed Image Text:The no-load voltage in the voltage-divider circuit shown in Fig. P3.140 is 8 V. The smallest load resistor that is ever connected to the divider is 3.6 kN. When MULTISIM PROBLEM the divider is loaded, v, is not to drop below 7.5 V. Figure P3.14 R1 40 V R2 v. §RL a. Design the divider circuit to meet the specifications just mentioned. Specify the numerical values of Rị and Rg. b. Assume the power ratings of commercially available resistors are 1/16, 1/8, 1/4, 1, and 2 W. What power rating would you specify?
Expert Solution
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A voltage divider can be used to scale down an extremely high voltage so that a voltmeter can read it. The divider output, which outputs a lower voltage that is within the meter's input range, is detected by the meter after the high voltage is placed across it. The voltage across any resistor in a series connection of resistors must be equal to the resistor's value divided by the circuit's equivalent resistance. This is referred to as the Voltage Division Rule.

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