An electrical engineer designed an RL circuit similar to the one shown in the figure, with E = 6.00 V, L = 2.00 mH, and R = 3.40 N.LR(a) What is the inductive time constant of the circuit (in ms)?0.588ms(b) Calculate the current in the circuit (in A) 250 µs after the switch is closed.0.61A(c) What is the value of the final steady-state current (in A)?0.98Apply Ohm's law. A(d) After what time interval (in ms) does the current reach 80.0% of its maximum value?1.171o[1 - exp(- ).with i = 0.800I,: Use your value from part (c) for I, and the inductiveApply the equation for the current as a function of time in an RL circuit, i = I,time constant found in part (a). msNeed Help?Read Itll

Givenε=6 VL=2 mH=2×10-3 HR=3.4 Ω

Answered: R What is the inductive time constant…

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R What is the inductive time constant of the circuit (in ms)? 0.588 ms

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter33: Inductors And Ac Circuits

Section: Chapter Questions

Problem 36PQ

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Question

An electrical engineer designed an RL circuit similar to the one shown in the figure, with E = 6.00 V, L = 2.00 mH, and R = 3.40 N.
L
R
(a) What is the inductive time constant of the circuit (in ms)?
0.588
ms
(b) Calculate the current in the circuit (in A) 250 µs after the switch is closed.
0.61
A
(c) What is the value of the final steady-state current (in A)?
0.98
Apply Ohm's law. A
(d) After what time interval (in ms) does the current reach 80.0% of its maximum value?
1.17
1o[1 - exp(- ).
with i = 0.800I,: Use your value from part (c) for I, and the inductive
Apply the equation for the current as a function of time in an RL circuit, i = I,
time constant found in part (a). ms
Need Help?
Read It
ll

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