Question 1 10 points Save Answer The Industrial Engineering at Shocker Communications has devised one alternative method involving new tooling for a job being machined in the shop. Data on the present and proposed method are shown in the table below. What production quantity would be required for the alternative method to be more economical? Assume the base pay rate is $10.0 per hour. The estimated production quantity is 15040 per year. The fixtures are capitalized and depreciated in 4 years. Round your answer to the closest integer. Method Standard Time (min) Fixture Cost Tool Cost Average Tool Life Present 10,000 0.856 10 $6 Method pieces 32845 Alternative 0.791 $930 $20 pieces

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter12: Sequences, Series And Binomial Theorem
Section12.3: Geometric Sequences And Series
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The Industrial Engineering at Shocker Communications has devised one alternative method involving new tooling for a job being machined in the
shop. Data on the present and proposed method are shown in the table below. What production quantity would be required for the alternative
method to be more economical? Assume the base pay rate is $10.0 per hour. The estimated production quantity is 15040 per year. The fixtures
are capitalized and depreciated in 4 years. Round your answer to the closest integer.
Method
Standard
Time (min)
Fixture
Cost
Tool Cost
Average
Tool Life
Present
10,000
0.856
10
$6
Method
pieces
32845
Alternative 0.791
$930
$20
pieces
Transcribed Image Text:Question 1 10 points Save Answer The Industrial Engineering at Shocker Communications has devised one alternative method involving new tooling for a job being machined in the shop. Data on the present and proposed method are shown in the table below. What production quantity would be required for the alternative method to be more economical? Assume the base pay rate is $10.0 per hour. The estimated production quantity is 15040 per year. The fixtures are capitalized and depreciated in 4 years. Round your answer to the closest integer. Method Standard Time (min) Fixture Cost Tool Cost Average Tool Life Present 10,000 0.856 10 $6 Method pieces 32845 Alternative 0.791 $930 $20 pieces
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