Problem 9: A horizontal force, F1 = 95 N, and a force, F2 = 19.7 N acting at an angle of θ to the horizontal, are applied to a block of mass m = 2.1 kg. The coefficient of kinetic friction between the block and the surface is μk = 0.2. The block is moving to the right. Randomized VariablesF1 = 95 N F2 = 19.7 N m = 2.1 kg Part (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°. Part (b) Solve numerically for the magnitude of acceleration
Problem 9: A horizontal force, F1 = 95 N, and a force, F2 = 19.7 N acting at an angle of θ to the horizontal, are applied to a block of mass m = 2.1 kg. The coefficient of kinetic friction between the block and the surface is μk = 0.2. The block is moving to the right. Randomized VariablesF1 = 95 N F2 = 19.7 N m = 2.1 kg Part (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°. Part (b) Solve numerically for the magnitude of acceleration
College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Introduction
Section: Chapter Questions
Problem 12P: The radius of a circle is measured to be (10.5 0.2) m. Calculate (a) the area and (b) the...
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Problem 9: A horizontal force, F1 = 95 N, and a force, F2 = 19.7 N acting at an angle of θ to the horizontal, are applied to a block of mass m = 2.1 kg. The coefficient of kinetic friction between the block and the surface is μk = 0.2. The block is moving to the right.
Randomized VariablesF1 = 95 N
F2 = 19.7 N
m = 2.1 kg
Part (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°.
Part (b) Solve numerically for the magnitude of acceleration of the block, a in m/s2, if θ = 30°.
SO FOR A I GOT 10.73 AND IT WAS WRONG
AND FOR B I GOT 52.34 WHAT AM I DOING WRONG??????///
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