Problem #2. The circuit below shows a Common Emitter (C.E.) configuration with the following arameters: Rg= 100 kN, Rc=8 kN, Rsig = 5 kN, R₂ = 5 kN, Vr= 25 mV, C₂= 1 pF, C₂=7 pF, C£= 75 µF. The small signal parameters have been calculated to be gm = 40 mA/V, rz=2.5 KQ Vcc _nd ro= ∞0. 2 this Re -VEE R₂

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Problem #2. The circuit below shows a Common Emitter (C.E.) configuration with the following
parameters: RB = 100 k, Rc=8 kN, Rsig = 5 k2, R₁ = 5 kN, Vr= 25 mV, C₂= 1 pF, C₂= 7 pF,
CE= 75 µF. The small signal parameters have been calculated to be gm = 40 mA/V, n = 2.5 KQ
and ro= ∞0.
Vcc
V
RL
Ris
this
-VEE
High-Frequency Analysis: Clearly draw the small signal high-frequency model (with the Hybrid-
7) and find all break frequencies. What is the upper 3-dB frequency (fi)?
Ra
Rc
Transcribed Image Text:Problem #2. The circuit below shows a Common Emitter (C.E.) configuration with the following parameters: RB = 100 k, Rc=8 kN, Rsig = 5 k2, R₁ = 5 kN, Vr= 25 mV, C₂= 1 pF, C₂= 7 pF, CE= 75 µF. The small signal parameters have been calculated to be gm = 40 mA/V, n = 2.5 KQ and ro= ∞0. Vcc V RL Ris this -VEE High-Frequency Analysis: Clearly draw the small signal high-frequency model (with the Hybrid- 7) and find all break frequencies. What is the upper 3-dB frequency (fi)? Ra Rc
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