Problem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation is 5.9 mm and the the electric field inside is 24 N/C. An electron is positioned halfway between the plates and is given some initial velocity, v₁. Randomized Variables d=5.9 mm E = 24 N/C · + + + + + + + d | | | | | | | | | | Otheexpertta.com Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? Part (b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its speed be, in meters per second, when it reaches the positive plate in this case? select part Vf,b=

Problem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation is 5.9 mm and the the electric field inside is 24 N/C. An electron is positioned halfway between the plates and is given some initial velocity, v₁. Randomized Variables d=5.9 mm E = 24 N/C · + + + + + + + d | | | | | | | | | | Otheexpertta.com Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? Part (b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its speed be, in meters per second, when it reaches the positive plate in this case? select part Vf,b=

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation is 4.7 mm and the the electric field inside is 26 N/C. An electron is positioned halfway between the plates and is given some initial velocity, v₁. Randomized Variables d=4.7 mm E = 26 N/C Vi,a + + + + + + + + Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? d
An evacuated tube uses an accelerating voltage of 26.026.0-kV to accelerate electrons to hit a copper plate and produce x-rays. Non-relativistically, what would be the maximum speed of these electrons? Enter your answer to 3 sigfigs in the coefficient and in calculator notation. Ex: 3.00E8. This problem required units.
... Path of trajectory AV w An electron is fired at a speed v¡ = 3.4 x 106 m/s and at an angle 0; = 30.5° between two parallel conducting plates as shown in the figure. If s = 1.5 mm and the voltage difference between the plates is AV = 98 V, determine how close, w, the electron will get to the %3D %3D bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.
A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. Randomized Variables E = 2.7 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.7 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.
An electron is fired at a speed vi = 4.1 × 106 m/s and at an angle θi = 38.2° between two parallel conducting plates as shown in the figure. If s = 1.9 mm and the voltage difference between the plates is ΔV = 98.3 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer.
In Fig. 1, two parallel-plate capacitors (with air between theplates) are connected to a battery. Capacitor 1 has a plate areaof 1.5 cm2 and an electric field (between its plates) ofmagnitude 2000 V/m. Capacitor 2 has a plate area of 0.70 cm2and an electric field of magnitude 1500 V/m. What is the totalcharge on the two capacitors?
Problem 3.01. (a) Find the electric field between two plates which are separated along the y-axis Ay = 6.00 mm, where the bottom plate has a potential V₂ = 150. mV and the top plate has a potential V₁ = 5.00 mV. (b) What is the potential at a distance Ay' = 2.00 um from the bottom plate?
Answers: a) 3.3 C c/m² 6. Two electrons are fixed 2.00 cm apart. Another electron is shot from infinity and comes to rest midway between the two. What was its initial speed? Answer: 318 m/s
Fig.2
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= 2. In an electrode system potential equation is given as V(x, y) x are; for x =0.5 cm, y=1 cm V = V₁ =40 kV and x =1 cm, y=1cm V = V₂ =0 V. a) Determine the constant A and B. b) Evaluate electric field equation. Determine maximum and minimum electric field strength values. A + By and the boundary conditions