Problem 11. An alternating voltage, v, has a periodic time of 0.01 s and a peak value of 40 V. When time t is zero, v= -20 V. Express the instantaneous voltage in the form v=Vm sin(wto).

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Problem 11. An alternating voltage, v, has a periodic
time of 0.01 s and a peak value of 40 V. When time t is
zero, v= -20 V. Express the instantaneous voltage in
the form v=Vm sin(wt + p).
Transcribed Image Text:Problem 11. An alternating voltage, v, has a periodic time of 0.01 s and a peak value of 40 V. When time t is zero, v= -20 V. Express the instantaneous voltage in the form v=Vm sin(wt + p).
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